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3 years ago

Find the area of a rectangle with a length of 12 feet and a width of 24 feet

Mathematics

2 answers:

laiz [17]3 years ago

6 0

The answer is 288 Sq Ft

Ludmilka [50]3 years ago

5 0

A=12 times 24=

288ft^2

Hope it helped!

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HELP RIGHT NOW AND ILL GIVE BRAINLY IF CORRECT

Stella [2.4K]

Answer:

-9

Step-by-step explanation:

$3^{-36}$ = $27^{-12}$

7 0

3 years ago

Using all of the digits 1-9 (1, 2, 3, 4, 5, 6, 7, 8, 9) in that order and the operations +, - create 4 different equations with

alexandr1967 [171]

5 + 6 + 89

4 + 7 + 89

24 + 67 + 9

1 + 23 + 67 + 9

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4 years ago

an inverted cone has a height of 11 inches and an initial radius of 18 inches. the volume of the inverted cone is decreasing at

joja [24]

Radius of cone is decreasing at the rate of $\frac{1623}{110\pi}$ inches

What is rate of change?

Suppose there is a function and there are two quantities. If one quantity of a function changes, the rate at which other quantity of the function changes is called rate of change of a function.

Here rate of change of radius of cone has been calculated

Radius of cone = 18 inches

Height of cone = 11 inches

Volume of cone (V) = $\frac{1}{3} \pi r^2h$

$\frac{dV}{dt} = \frac{1}{3} \pi h (2r\frac{dr}{dt})\\-541 = \frac{2}{3} \pi \times 11\times 5\times\frac{dr}{dt}\\\frac{dr}{dt} = -\frac{541 \times 3}{2 \times \pi \times 11 \times 5}\\\frac{dr}{dt} = -\frac{1623}{110 \pi}$

Radius of cone is decreasing at the rate of $\frac{1623}{110\pi}$ inches

To learn more about rate of change, refer to the link-

brainly.com/question/24313700

#SPJ4

5 0

2 years ago

Stacey has a square piece of cloth. She cuts 3 inches off of the length of the square and 3 inches

Mamont248 [21]

Answer:

6 in

Step-by-step explanation:

Let x = the side length of the original square.

They removed 3 in from each side of the original square, so the side lengths of the remaining square are x - 3 in.

The area of the smaller square is (x - 3)².

The area of the original square is x²

I assume the area of the smaller square is ¼ that of the original square. Then

1. Solve for x

$\begin{array}{rcl}\frac{1}{4}x^{2} & = & (x - 3)^{2}\\x^{2} & = & 4(x - 3)^{2}\\& = & 4(x^{2} - 6x + 9)\\x^{2}& = & 4x^{2} - 24x + 36\\3x^{2} - 24x + 36 & = & 0\\x^{2} - 8x + 12 & = & 0\\(x - 2)(x - 6) & = & 0\\x - 2 = 0& \qquad &x - 6 = 0\\x = 2& \qquad &x = 6\\\end{array}$

2. Calculate the side length of the smaller square

(a) x = 2

Side length = x - 3 = 2 - 3 = -1 in.

IMPOSSIBLE. You can't have a negative side length.

(b) x = 6

Side length of smaller square = 6 - 3 = 3 in.

Side length of original square = x = 6 in

Check:

$\begin{array}{rcl}\frac{1}{4}(6)^{2} & = & (6 - 3)^{2}\\\frac{1}{4}\times 36 & = & 3^{2}\\9 & = & 9\\\end{array}$

OK.

3 0

3 years ago

Please help please please please please

Bess [88]

One dice has 6 sides and two dice will give us 12 sides with 36 possibilities
it will be 9/36=.25

so it will have 25% chance of the two dice to have a sum of 9

5 0

3 years ago