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ICE Princess25 [194]

3 years ago

13

Question is in the image

1 answer:

vova2212 [387]3 years ago

3 0

If I am not mistaken, it is D

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Write the equation of a line in slope-intercept form that goes through the points

Stella [2.4K]

Answer: The equation in slope-intercept form is y=2x-11

Step-by-step explanation: Slope-intercept is y=mx+b where m is the slope and b is the y-intercept. To find the slope, you find the difference between the y values divided by the difference between the x values. -5-(-9) = 4, and 3-1 is 2. 4/2 is 2, so m = 2. Since the slope is 2, it states for every x you move on the right you move 2 up. But we are trying to get the y-intercept, so x = 0. We are subtracting 1 in our x value, so we move 2 downwards. We subtract 2 from -9 which gives us -11, which is our y-intercept.

Hope this helps!

5 0

3 years ago

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

so

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

3 years ago

The circumference of a circle is 5(pie). Which of these correctly states the diameter? Please explain and dont just write the le

sattari [20]

Answer: C. 5

Step-by-step explanation:See the attached picture.

8 0

3 years ago

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∫(x+1)/(x2+2)2x−3dx need help with this question. can you show the process

kenny6666 [7]

do you need to include the wiggle infront of the first bracket? if not;

(x+1) ÷ [(x^2+2) x (2x-3dx)]

x^2 x 2x = 2x^3

x^2 x -3dx = -3dx^3

2 x 2x = 4x

2 x -3dx = - 6dx

i cant find a way to make it equal 0 so i think the answer is just

x+1 over 2x^3 - 3dx^3 + 4x - 6dx as a fraction

4 0

3 years ago

Owen simplified the expression r-8 s-5.<br><br><br>r−8s−5 = 1r8 ⋅ s5 = s5r8

kobusy [5.1K]

r⁻⁸ s⁻⁵

using the rule x⁻ⁿ=1/xⁿ

r⁻⁸ s⁻⁵ = (1/r⁸)(1/s⁵)

6 0

4 years ago

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