Answer:
1 3/7 quarts should be drained off and replaced with pure antifreeze.
1 3/7 ≈ 1.4286
Current amount of antifreeze in quarts is -
30/ 100 × 10 = 3
40% ---> 4 quarts
Let the amount drained of and replaced with antifreeze be x-
The amount left after draining off is 10 − x.
The amount of antifreeze is 30/ 100 (10−x).
30/100(10-x)+x=4
3-3/10x+x=4
3+x(1-3/10)=4
x=1*10/7=1 3/7 quarts
check;
10- 1 3/7 = 8 4/7
=(30/100*8 4/7)+1 3/7
=(3/10 * 60/7) + 10/7
=3*6/7 + 10/7
=28/7
=4
4 liters of pure antifreeze is mixed into 10 quarts.
Answer:
Step-by-step explanation:
Daily temp(in F) Cakes sold
42 39
45 52
48 31
54 61
59 72
62 35
64 61
65 34
67 58
75 45
84 24
To find whether there is an association between these two let us find the correlation coefficient between these two variables.
r=-0.1975
Since |r|<0.5, correlation is weak.
Let us test the hypothesis r =0
H0:r=0
Ha:r not equals 0
Test statistic = 
p =0.298
Since p value >0.10, at 90% significance level we accept that there is no association.
(4y³ + 4y²+8)(6y - 4)
Simplify.
24y⁴ - 16y³ + 24y³ - 16y² + 48y - 32
Add like terms.
24y⁴ + (-16y³ + 24y³) -16y² + 48 - 32
Simplify.
24y⁴ + 8y³ - 16y³ + 16
~Hope I helped!~
Answer:
15:25
Step-by-step explanation:
15 correct from 25 total
