The maximum speed of a boat at 30 feet length of water is 0.093 nautical miles/hour or knots.
<u>Step-by-step explanation:</u>
- The equation for the maximum speed, s is given by s²= (16/9)x
- where, x is the length of the water line in feet.
It is given that, the modeled equation s²= (16/9)x is used to find the maximum speed in knots or nautical miles per hour.
The question is asked to find the maximum speed when the length of the water is 30 feet.
Therefore, to find the maximum speed in 30 feet water, the given modeled equation is used. So, substitute the 30 feet in place of x.
<u>Now, calculating the maximum speed :</u>
s² = (16/9)(30)
s² = 480 / 9
s² = 53.3
Taking square root on both sides,
s = √53.3
s = 7.3
The maximum speed of a boat at 30 feet length of water is 7.3 nautical miles/hour or knots.
M + w + c = 2838
w = 3c + 5
m = 4w - 3......4(3c + 5)- 3 = 12c + 20 - 3 = 12c + 17
(12c + 17) + (3c + 5) + c = 2838 .....combine like terms
16c + 22 = 2838
16c = 2838 - 22
16c = 2816
c = 2816/16
c = 176 <==== children
w = 3c + 5
w = 3(176) + 5
w = 533 <=== women
m = 12c + 17
m = 12(176) + 17
m = 2129 <=== men
Step-by-step explanation:
n (U)=2000
n (A)=50% of 2000
=(50÷100)×2000
= 1000
n( B) = 40%
= (40÷100)×2000
= 800
n(AuB)(compliment) = 15%
=(15÷100)×2000
=300
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I hope you know how to make a Venn diagram.
Mark me as a brainliest
3n - 1
When n = 1,
3n - 1 = 3*1 - 1 = 3 -1 = 2
When n = 2,
3n - 1 = 3*2 - 1 = 6 -1 = 5
When n = 3,
3n - 1 = 3*3 - 1 = 9 -1 = 8
Hence, the first three terms are 2, 5 and 8.
Answer:
QR = 48 units
Step-by-step explanation:
in a rectangle, opposite sides are equal
so QR = PS and QP = RS
also we know that the sum of all sides is the perimeter, which is 176
we can set up this equation:
2(5z - 2) + 2(4z) = 176
10z - 4 + 8z = 176
18z - 4 = 176
18z = 180
z = 10
QR = 5z - 2
we can substitute 10 for 'z' to get:
5(10) - 2 = 50 - 2 or 48
Check:
2(48) + 2(40) = 176
96 + 80 = 176
176 = 176
