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Lilit [14]
4 years ago
9

A triangle has the coordinates A( 4, –1), B(3, –3), and C(0, 2). Reflect the triangle over the y-axis and find the coordinates o

f its image. A(4, −1) → A'(, ) B(3, −3) → B'(, ) C(0, 2) → C'(, )
Mathematics
1 answer:
skelet666 [1.2K]4 years ago
8 0

Answer:  A(4,-1)-> A'(-4,-1) .   B(3,-3)->B'(-3, -3) .  C(0,2) -> C' (0,2)

Step-by-step explanation:

Pls note that any point P with coordinates Xp and Yp refecting over y-axis will have the image P' with coordinates  -Xp  and Yp.

So the image of A(4,-1)-> A'(-4,-1)

image of B(3,-3)->B'(-3, -3)

image of C(0,2) -> C' (0,2)    C reflects to itself  

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Solve the polynomial inequality x^2-3x-10>0
djverab [1.8K]

As x² - 3x - 10 factors, we can use the zero product property and pull it apart into factors. It factors because 2 and 5 have a difference of 3 and product of 10

x² - 3x - 10 > 0

(x - 5)(x + 2) > 0

To find where the inequality is true, we use a sign test. When x-5 > 0, it means x >5, and 5 is one of our sign test values. Similarly, -2 is the other. We can then make three intervals - A (less than -2), B (between -2 and 5), and C (more than 5).

<--------------- -2 ------------------ 5 -------------------------->

A B C

To do a sign test, we choose values to see what happens. First, test x = -5.

(-5 - 5)(-5 + 2) = (-10)(-3) = 30. Because 30 > 0, the inequality is true for x < -2. So interval A is true.

Next, test x = 0.

(0 - 5) (0 + 2) = (-5)(2) = -10. Because -10 < 0 is false, the inequality is false for x > -2 and x < 5. So interval B is false.

Last, test x = 10

(10 - 5) (10 + 2) = (5) (8) = 40. Because 40 > 0 is true, the inequality is true for x > 5. So interval C is true.

We put the true intervals together.

(-∞, -2) ∪ (5, ∞) is where this inequality is true,

{x : x < -2 or x > 5} is also how it's said in set notation.

7 0
3 years ago
What is the equation of the line that passes through the point (4,-7) and has a
aalyn [17]

Answer:

y = -\frac{1}{2} x -5

point slope form....

y - (-7) = -1/2(x-4)

y + 7 = -x/2 + 2

2y + 14 = -x + 4

2y = -x -10

y = -1/2 x - 5

Step-by-step explanation:

7 0
3 years ago
Find the Number in Each Case
ipn [44]
It seems like you have the answer already. but heres how its calculated.
\frac{100}{15} = \frac{?}{3} 
so the missing number is 20 **cross multiply 100 and 3 to get 300 then divide 15 into 300 to get 20**

\frac{160}{100} =  \frac{80}{?} 
so the missing number is 50
 **cross multiply 100 and 80 to get 8000 then divide 160<span> into 8000 to get 50**</span>

 
6 0
4 years ago
Does (2,0) work as a solution to the systems of equations to lines 3x+y=6 and 3x-y=6
fenix001 [56]

Answer:

Yes

Step-by-step explanation:

To see if (2,0) works as a solution to the systems of equations, we plug in the values of x and y and simplify. If the results are equal, then (2,0) is a solution.

3x + y = 6:

  • 3(2) + 0 = 6
  • 6 + 0 = 6
  • 6 = 6
  • (2,0) is a solution to this equation.

3x - y = 6:

  • 3(2) - 0 = 6
  • 6 - 0 = 6
  • 6 = 6
  • (2,0) is a solution to this equation.

Therefore, the answer is yes, it does work as a solution.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

7 0
3 years ago
Order the following numbers from least to greatest.
TEA [102]

Answer:

-5.2, -4.75, -9/2

Step-by-step explanation:

8 0
2 years ago
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