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Archy [21]
4 years ago
6

he coordinates below are the three vertices of a rectangle. Identify the fourth coordinate and the area of the rectangle. A coor

dinate plane with the following points A at negative 2, 2; B at negative 2, negative 3; and C at 7, negative 3.
Mathematics
1 answer:
Paraphin [41]4 years ago
8 0

Answer:

The answer is 7,2

Step-by-step explanation:

All of the numbers are different like possitive, negitive. and negitive, negitive along with negitive, possitive leaving us left with possitive, possitive and if you look on a coordinate plane you can make a rectangle with all of these coordinates put together. Hope this helps! :D

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leonid [27]
Let's assign the width to a variable, with that variable being x. the length is two times the width, so it would be 2x. the perimeter of a rectangle is length + length + width + width, so you would add 2x + 2x + x + x = 24 inches. combine like terms (x) to get 6x = 24. divide both sides by 6 to get x = 4. so the width (x) is 4, and the length (2x) is 8. the area of a rectangle is length times width, so multiply 4 * 8. that would get you 32 inches^2.
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4 years ago
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Sedaia [141]

Answer:

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4 years ago
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3 years ago
P^2 - 4p - 32 / p + 4, simplify the rational expression. state any restrictions
dusya [7]

Answer:

The correct answer is: p - 8 ∧ restriction p ≠ -4

Step-by-step explanation:

(p² - 4 p - 32) / ( p + 4)

The existence of this rational algebraic expression is possible only if it is:

p + 4 ≠ 0  => Restriction is p ≠ -4

(p² - 4 p - 32) / ( p + 4) = (p² - 8 p + 4 p - 32) / (p + 4) =

= (p (p -8) + 4 (p -8)) / (p + 4)= (p - 8) (p + 4) / ( p +4) = p - 8

God with you!!!

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