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nekit [7.7K]
3 years ago
14

What is the greatest possible product of a 3 digit number and a 1 digit number?

Mathematics
2 answers:
nydimaria [60]3 years ago
3 0
To figure this out, we must multiply the highest 3 digit number and the highest 1 digit number together.

9 is the highest 1 digit number.
999 is the highest 3 digit number.

999 × 9 = 8991

The greatest possible product is 8,991.
Serjik [45]3 years ago
3 0
The greatest possible product is what you get when both numbers are
as big as they can be.

The greatest possible  3-digit number is  999 .

The greatest possible  1-digit number is  9 .

Their product is  (999 x 9) = <em>8,991 .</em>




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An aircraft has a maximum of 30 first class seats and 220 economy seats.
Sidana [21]

Answer:

x\leq 30

y\leq 220

240x+120y

Step-by-step explanation:

Let

x ----> the number of first class seats

y ----> the number of economy class seats

we know that

An aircraft has a maximum of 30 first class seats

so

x\leq 30

An aircraft has a maximum of 220 economy seats

y\leq 220

A flight will be cancelled if the money taken for the seats is less than $28,800.

so

240x+120y

therefore

Three inequalities that represent the situation are

x\leq 30

y\leq 220

240x+120y

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The amounts of time employees of a telecommunications company have worked for the company are normally distributed with a mean o
Fynjy0 [20]

Answer:

a) 5.6 years

b) 0.4478

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 5.6 years

Standard Deviation, σ = 1.9 years

Sample size, n = 18

We are given that the distribution of amounts of time is a bell shaped distribution that is a normal distribution.

a) Mean of each sample.

The best estimator of the sample mean is the population mean itself. Thus, we have:

\mu_{x} = \mu = 5.6

Thus, the sample mean is 5.6 years.

b) Standard error

Formula:

S.E = \dfrac{\sigma}{\sqrt{n}}

Putting values, we have.

S.E = \dfrac{1.9}{\sqrt{18}} = 0.4478

Thus, the standard error is 0.4478.

7 0
3 years ago
A circle in the standard (x,y) coordinate plane has
Otrada [13]

Given:

Center of a circle is at point C(-1,2).

AB is the diameter of the circle.

Coordinates of the point A are A(2,6).

To find:

The coordinates of point B.

Solution:

Let the coordinates of point B are (a,b).

If AB is the diameter of the circle, then A and B are end points of diameter of the circle and the center C is the midpoint of AB.

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Point C = Midpoint of AB

(-1,2)=\left(\dfrac{2+a}{2},\dfrac{6+b}{2}\right)

On comparing both sides, we get

\dfrac{2+a}{2}=-1

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Similarly,

\dfrac{6+b}{2}=2

6+b=2\times 2

b=4-6

b=-2

Therefore, the coordinates of point B are (-4,-2).

8 0
3 years ago
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