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3 years ago

8

Find the distance between the pair of points given on the graph

1 answer:

seraphim [82]3 years ago

7 0

<em>The</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>√</em><em>7</em><em>4</em><em> </em><em>units</em><em>.</em>

<em>Pl</em><em>ease</em><em> </em><em>see</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>for</em><em> full</em><em> solution</em>

<em>H</em><em>ope</em><em> it</em><em> helps</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

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A triangle has a hypotenuse that is 60 inches, and the length of one of its legs is 36 inches. What is the length, in inches, of

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Answer:

48

Step-by-step explanation:

think of the a squared plus b squared equals c squared. plug in the 36 in either b or a. then plug in the 60 in c's spot. solve and get 48. you can check the answer by solving 48 squared plus 36 squared equals 60 squared. both sides are equal and both come out to be the 3600

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Find the area of a triangle bounded by the y-axis, the line f(x)=9−2/3x, and the line perpendicular to f(x) that passes through

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Answer:

The area of the triangle is 18.70 sq.units.

Step-by-step explanation:

It is provided that a triangle is bounded by the y-axis, the line $f(x)=y=9-\frac{2}{3}x$ .

The slope of the line is: $m_{1}=-\frac{2}{3}$

A perpendicular line passes through the origin to the line f (x).

The slope of this perpendicular line is: $m_{2}=-\frac{1}{m_{1}}=\frac{3}{2}$

The equation of perpendicular line passing through origin is:

$y=\frac{3}{2}x$

Compute the intersecting point between the lines as follows:

$y=9-\frac{2}{3}x\\\\\frac{3}{2}x=9-\frac{2}{3}x\\\\\frac{3}{2}x+\frac{2}{3}x=9\\\\\frac{13}{6}x=9\\\\x=\frac{54}{13}$

The value of <em>y</em> is:

$y=\frac{3}{2}x=\frac{3}{2}\times\frac{54}{13}=\frac{81}{13}$

The intersecting point is $(\frac{54}{13},\ \frac{81}{13})$ .

The <em>y</em>-intercept of the line f (x) is, 9, i.e. the point is (0, 9).

So, the triangle is bounded by the points:

(0, 0), (0, 9) and $(\frac{54}{13},\ \frac{81}{13})$

Consider the diagram attached.

Compute the area of the triangle as follows:

$\text{Area}=\frac{1}{2}\times 9\times \frac{54}{13}=18.69231\approx 18.70$

Thus, the area of the triangle is 18.70 sq.units.

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