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Free_Kalibri [48]
3 years ago
12

Three members (mary ,sue and tom of a 20-person office of carpooling so they insit on never working seperatly. that is whenever

one of them is on a committe all three must be. How many committes of size 7 meet this requirment.
Mathematics
1 answer:
AlekseyPX3 years ago
4 0

Answer:

2380 committees of size 7 meet the given requirement.

Step-by-step explanation:

The question is basically asking us to find the number of ways in which 7 persons can be selected in a committee, such that 3 members ( Mary, Sue and Tom ) are always included.

Now, there are a total of 20 persons in the office, out of which 3 members are always included in the committee.

So, 3 members can be selected in 3_C__3 ways.

Now, 4 members are to be selected  out of the remaining 17  persons in the office.

So 4 members can be selected in 17_C__4 ways.

And so the total number of ways of selecting 7-member committee with the given requirement = 3_C__3 x 17_C__4 = 2380 ways.

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Start by making the denominators of both fraction the same. This can be done by multiplying one fraction's denominator by the other.

After simplifying and combining the two fractions together, check if the numerator can be factorised such that there is a common factor in the denominator and numerator. In this case, the numerator cannot be factorised.

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see above

.............

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