Question

The interior angles of a quadrilateral are 2x+15 2x-5 3x+75 3x-25 find x and the smallest interior angle largest interior angle and smallest exterior angle

Answer 1

Answer:$x=30^{\circ}$

Step-by-step explanation:

We know sum of the interior angles of a quadrilateral is $360^{\circ}$

therefore  we can write

$(2x+15)+(2x-5)+(3x+75)+(3x-25)=360^{\circ}$

so

$\Rightarrow 10x+60=360$

$\Rightarrow 10x=300$

$\Rightarrow x=30^{\circ}$

So smallest interior angle is $(2x-5)^{\circ}=(60-5)=55^{\circ}$

Largest interior angle $=3x+75=90+75=165^{\circ}$