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Aleks04 [339]
3 years ago
9

If a textbook has a mass of 2.2kg and weighs 19.6 newtons on Venus what is the strength of gravity on Venus?

Mathematics
1 answer:
Neporo4naja [7]3 years ago
7 0
G=mg=>g=G/m=8,9m/s^2
You might be interested in
A Mercedes can go 78 miles on 3 gallons of gas. How far can it go with a full tank of 16 gallons?
Alex787 [66]

Answer:

416 miles

Step-by-step explanation:

78 divided by 3 = 26

26 x 16 = 416

5 0
2 years ago
At Stephanie's new job, she spent $6.50, $8, $7.25, $13.50, and $9.75 on lunch the first week. In the second week, Stephanie spe
MaRussiya [10]

Answer:

The mean for the second week is $2 less than the first and in percentage it is 22% less.

Step-by-step explanation:

The mean is given by the sum of all individual values divided by the number of values. For the first week the sum is:

sum1 = 6.5 + 8 + 7.25 + 13.5 + 9.75

sum1 = 45

Since she spent 10 less in the second week the sum is:

sum2 = sum1 - 10 = 45 - 10 = 35

The mean for each week is:

mean1 = sum1/5 = 45/5 = 9

mean2 = sum2/5 = 35/5 = 7

difference = mean1 - mean2 = 9-7 = 2

difference(%) = [2/9]*100 = 0.22*100 = 22%

The mean for the second week is $2 less than the first and in percentage it is 22% less.

6 0
3 years ago
Dog food costs 9$ per bag and cat food costs 8$ per bag. if billy spent 89$ and purchased 6 bags of dog food, how many bags of c
REY [17]
6 bags of dog food × $9 = 54
$89 total - $54 spent on dog food = $35 spent on cat food

$35 / $8 = 4.375, but you can't have decimals for cat food bags so round down.

= 4 bags of cat food
3 0
3 years ago
A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2
Yuliya22 [10]

A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2 and 5.1.

Answer: The correct option is B) about 34%

Proof:

We have to find P(4.2

To find P(4.2, we need to use z score formula:

When x = 4.2, we have:

z = \frac{x-\mu}{\sigma}

          =\frac{4.2-5.1}{0.9}=\frac{-0.9}{0.9}=-1

When x = 5.1, we have:

z = \frac{x-\mu}{\sigma}

          =\frac{5.1-5.1}{0.9}=0

Therefore, we have to find P(-1

Using the standard normal table, we have:

P(-1= P(z

                               =0.50-0.1587

                               =0.3413 or 34.13%

                               = 34% approximately

Therefore, the percent of data between 4.2 and 5.1 is about 34%

7 0
3 years ago
Draw a quick picture to show the number 68 In two ways
enot [183]
You can draw two quarters, a dime, a nickel, and three pennies. Or 6 dimes and 8 pennies.
7 0
3 years ago
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