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vova2212 [387]
3 years ago
5

The roles of the nurse in working with clients and families include which of the following?

Biology
1 answer:
vodomira [7]3 years ago
8 0
I believe the correct answer is B
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Question is below, plz help
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Both are 50%, this is because Rr is dominant in a purple stem and rr is recessive in a green stem. By crossing these plants Rxr= Rr and rxr= rr.
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Compare and contrast the contributions of Neel, Pauling, and Ingram to our understanding of the genetic and molecular basis of s
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He demonstrated that SCD and sickle cell trait were due to the presence of abnormal 8-globin polypeptides in red blood cells. He demonstrated that the electrophhoretic mobility of B-globin from patients with SCD was different from that of healthy individuals. He demonstrated that both parents of multiple patients with SCD had low levels of sickled red blood cells. He hypothesized that SCD was a recessive trait and that the parents of patients with SCD would be heterozygous carriers. He demonstrated that the difference between B-globin polypeptides in individuals who were healthy and those with SCD is an amino acid substitution. He performed a peptide fingerprint analysis on B-globin from individuals with 84 84 and 89 88, which identified the segment of B-globin that was changed by the BS mutation. James Neel Linus Pauling Vernon Ingram

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7 0
3 years ago
What is a sacrolemma?
Alexeev081 [22]

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the fine transparent tubular sheath which envelops the fibres of skeletal muscles.

6 0
3 years ago
Which evidence suggests that Earth's current warming trends are different
Scilla [17]

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6 0
3 years ago
A fish maintains its depth in fresh water by adjusting the air content of porous bone or air sacs to make its average density th
Volgvan

Answer:

0.153

Explanation:

We know the up-thrust on the fish, U = weight of water displaced = weight of fish + weight of air in air sacs.

So ρVg = ρ'V'g + ρ'V"g where ρ = density of water = 1 g/cm³, V = volume of water displaced, g = acceleration due to gravity, ρ'= density of fish = 1.18 g/cm³, V' = initial volume of fish, ρ"= density of air = 0.0012 g/cm³ and V" = volume of expanded air sac.

ρVg = ρ'V'g + ρ"V"g

ρV = ρ'V'g + ρ"V"

Its new body volume = volume of water displaced, V = V' + V"

ρ(V' + V") = ρ'V' + ρ"V"

ρV' + ρV" = ρ'V' + ρ"V"

ρV' - ρ"V'  = ρ'V" - ρV"

(ρ - ρ")V'  = (ρ' - ρ)V"

V'/V" = (ρ - ρ")/(ρ' - ρ)

= (1 g/cm³ - 0.0012 g/cm³)/(1.18 g/cm³ - 1 g/cm³)

= (0.9988 g/cm³ ÷ 0.18 g/cm³)

V'/V" = 5.55

Since V = V' + V"

V' = V - V"

(V - V")/V" = 5.55

V/V" - V"/V" = 5.55

V/V" - 1 = 5.55

V/V" = 5.55 + 1

V/V" = 6.55

V"/V = 1/6.55

V"/V = 0.153

So, the fish must inflate its air sacs to 0.153 of its expanded body volume

5 0
3 years ago
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