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3 years ago

Find the surface area please.

Mathematics

1 answer:

Zinaida [17]3 years ago

8 0

Answer:

Surface Area = 86 cm^2

Step-by-step explanation:

Given:

Triangle,

b = 8 cm

h = 9 cm

Rectangle,

l = 10 cm

w = 5 cm

To Find:

Surface Area = ?

Solution:

Surface Area = b x h /2 + l x w

Surface Area = 8 x 9 / 2 + 10 x 5

Surface Area = 4 x 9 + 50

Surface Area = 36 + 50

Therefore, Surface Area = 86 cm^2

PLZ MARK ME AS BRAINLIEST!!!

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3 years ago

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Answer:

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Step-by-step explanation:

The decay of an isotope is represented by the following differential equation:

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Now, the time constant is cleared:

$\ln \frac{m(t)}{m_{o}} = -\frac{t}{\tau}$

$\tau = -\frac{t}{\ln \frac{m(t)}{m_{o}} }$

The half-life of a isotope ( $t_{1/2}$ ) as a function of time constant is:

$t_{1/2} = \tau \cdot \ln2$

$t_{1/2} = -\left(\frac{t}{\ln\frac{m(t)}{m_{o}} }\right) \cdot \ln 2$

The half-life difference between isotope B and isotope A is:

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If $\frac{m_{A}(t)}{m_{o,A}} = \frac{m_{B}(t)}{m_{o,B}} = 0.9$ , $t_{A} = 33\,days$ and $t_{B} = 43\,days$ , the difference in the half-lives of the isotopes is:

$\Delta t_{1/2} = \left|-\left(\frac{33\,days}{\ln 0.90} \right)\cdot \ln 2 + \left(\frac{43\,days}{\ln 0.90} \right)\cdot \ln 2\right|$

$\Delta t_{1/2} \approx 65.788\,days$

The approximate difference in the half-lives of the isotopes is 66 days.

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