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Bezzdna [24]
3 years ago
6

When Sanchez left his house this morning, his cell phone was 30% charged and it then started to lose 3% charge for each hour the

reafter. Write an equation for the function B(t), representing the charge remaining in Sanchez's battery, as a percentage, t hours after he left his house.
Mathematics
1 answer:
Radda [10]3 years ago
3 0

Answer:

The equation that represents the battery charge in Sanchez's phone as a percentage t hours after he left his house is B(t) = 30 - 3*t.

Step-by-step explanation:

The initial state of the battery on Sanchez's phone is 30% so in time t equals zero the battery should be at that value and as time progresses the battery should lose battery charge at a rate of 3% for each hour. We can write this in an equation form by taking the initial state and subtract it by the rate multiplied by the value of time. We have:

B(t) = 30 - 3*t

The equation that represents the battery charge in Sanchez's phone as a percentage t hours after he left his house is B(t) = 30 - 3*t.

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3 years ago
Describe the graph that would be used to solve the equation-x^2 + 4 = x+2
Rzqust [24]

Answer:

The values of x are x = -2 and x= 1.

Step-by-step explanation:

The given equation -x²+4 = x+2 can be written in the form of two functions as

y = -x²+4 which is a function representing parabola and

y = x+2 which is a straight line.

Now we will solve the given equation to find their points of intersection on graph. Their points of intersections will be the answer.

-x²+4 = x+2

-x²+4-x = x+2-x

-x²-x+4 = 2

-x²-x+4-2 = 2-2

-x²-x+2 = 0

Or x²+x-2=0

Now we will factorize the equation.

x²+2x-x-2=0

x(x+2)-1(x+2) = 0

(x+2)(x-1) = 0

x+2 = 0 ⇒x = -2

x-1 = 0 ⇒x = 1

For x = 1, y will be 3

and for x = -2, y will be 0

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3 years ago
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2 years ago
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Find one value of x that is a solution to the equation:<br>(x^2– 8)^2 + x^2 – 8 = 20<br>x=​
Kipish [7]

Answer:

x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)

Step-by-step explanation:

Solve for x:

-8 + x^2 + (x^2 - 8)^2 = 20

Expand out terms of the left hand side:

x^4 - 15 x^2 + 56 = 20

Subtract 20 from both sides:

x^4 - 15 x^2 + 36 = 0

Substitute y = x^2:

y^2 - 15 y + 36 = 0

The left hand side factors into a product with two terms:

(y - 12) (y - 3) = 0

Split into two equations:

y - 12 = 0 or y - 3 = 0

Add 12 to both sides:

y = 12 or y - 3 = 0

Substitute back for y = x^2:

x^2 = 12 or y - 3 = 0

Take the square root of both sides:

x = 2 sqrt(3) or x = -2 sqrt(3) or y - 3 = 0

Add 3 to both sides:

x = 2 sqrt(3) or x = -2 sqrt(3) or y = 3

Substitute back for y = x^2:

x = 2 sqrt(3) or x = -2 sqrt(3) or x^2 = 3

Take the square root of both sides:

Answer: x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)

8 0
3 years ago
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