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Bezzdna [24]
3 years ago
6

When Sanchez left his house this morning, his cell phone was 30% charged and it then started to lose 3% charge for each hour the

reafter. Write an equation for the function B(t), representing the charge remaining in Sanchez's battery, as a percentage, t hours after he left his house.
Mathematics
1 answer:
Radda [10]3 years ago
3 0

Answer:

The equation that represents the battery charge in Sanchez's phone as a percentage t hours after he left his house is B(t) = 30 - 3*t.

Step-by-step explanation:

The initial state of the battery on Sanchez's phone is 30% so in time t equals zero the battery should be at that value and as time progresses the battery should lose battery charge at a rate of 3% for each hour. We can write this in an equation form by taking the initial state and subtract it by the rate multiplied by the value of time. We have:

B(t) = 30 - 3*t

The equation that represents the battery charge in Sanchez's phone as a percentage t hours after he left his house is B(t) = 30 - 3*t.

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Help please! Need help solving
NISA [10]
For the perimeter you have to consider the EXTERNAL SHAPE ONLY:

a) the perimeter of half a circle WITHOUT ITS DIAMETER  is:
π.R - 2R → 3.14x1.5 - 2x1.5 → 1.71 cm

b) the perimeter of the rectangle WITHOUT THE UPPER SIDE is:
2.5+3+2.5 = 8 cm

Hence the perimeter of the figure is 1.71 + 8 = 9.71 cm

2) Area of the figure:
Area of half circle is π.R²/2 →3.14 x (1.5)²/2 → Area half circle = 3.5325 cm²
Area of rectangle = 2.5 x 3 = 7.5 cm²
Total area = 3.5325 + 7.5 = 11.0325 ≈ 11 cm²


3 0
3 years ago
Two chemicals A and B are combined to form a chemical C. The rate, or velocity, of the reaction is proportional to the product o
Keith_Richards [23]

Answer:

  32.1 g

Step-by-step explanation:

In each 3 grams of C, there are 2 grams of A and 1 gram of B. So, for some amount C, the amount remaining of A is 40 -(2C/3), and the amount remaining of B is (50 -C/3). Since the reaction rate is proportional to the product of these amounts, we have ...

  C' = k(40 -2C/3)(50 -C/3) = (2k/9)(60 -C)(150 -C) . . . for some constant k

This is separable differential equation with a solution of the form ...

  ln((150 -C)/(60 -C)) = at + b

We know that C(0) = 0, so b=ln(150/60) = ln(2.5). And we know that C(10) = 20, so ln(130/40) = 10a +ln(2.5) ⇒ a = ln(1.3)/10

Then our equation for C is ...

  ln((150 -C)/(60 -C)) = t·ln(1.3)/10 +ln(2.5)

__

For t=20, this is ...

  ln((150 -C)/(60 -C)) = 2ln(1.3) +ln(2.5) = ln(2.5·1.3²) = ln(4.225)

Taking antilogs, we have ...

  (150 -C)/(60 -C) = 4.225

  1 +90/(60 -C) = 4.225

  C = 60 -90/3.225 ≈ 32.093 . . . . . grams of product in 20 minutes

In 20 minutes, about 32.1 grams of C are formed.

7 0
3 years ago
Which of the following tables shows a rate greater than 1 kilometer per hour
LenKa [72]

Answer:

it is C

Step-by-step explanation:

4 0
3 years ago
(x+2) (y-5)=0<br> please help me graph and solve this!!
viktelen [127]
(X+2)(y-5)=0

X+2=0
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Y-5=0
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X is horizontal
Y is vertical
4 0
3 years ago
What is the least common multiple of 12 and 5​
Ket [755]

Answer:

least common multiple (LCM) of 5 and 12 is 60

4 0
3 years ago
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