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3 years ago

Which equation matches the graph?

Mathematics

2 answers:

kogti [31]3 years ago

8 0

Just match the x coordinates with the y one

lakkis [162]3 years ago

6 0

Answer:

Match the x coordinates with the y ones

Step-by-step explanation:

Basically that’s it

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The distance of planet Mercury from the Sun is approximately 5.8 ⋅ 107 kilometers, and the distance of Earth from the Sun is 1.5

ch4aika [34]

The answer is A: 4.3·107 kilometers

5 0

4 years ago

Read 2 more answers

Write the quadratic equation whose roots are 3 and -5, and whose leading coefficient is 2.

Rainbow [258]

$\begin{cases} x=3\implies &x-3=0\\ x=-5\implies &x+5=0 \end{cases}\qquad \implies\qquad a(x-3)(x+5)=\stackrel{0}{y} \\\\\\ a(\stackrel{F~O~I~L}{x^2+2x-15})=y\implies \stackrel{\textit{leading coefficient of 2}}{2(x^2+2x-15)}=y\implies 2x^2+4x-30=y$

Check the picture below.

5 0

3 years ago

Evaluate the sum of the following finite geometric series.

rjkz [21]

Answer:

$\large\boxed{\dfrac{156}{125}\approx1.2}$

Step-by-step explanation:

<h3>Method 1:</h3>

$\sum\limits_{n=1}^4\left(\dfrac{1}{5}\right)^{n-1}\\\\for\ n=1\\\\\left(\dfrac{1}{5}\right)^{1-1}=\left(\dfrac{1}{5}\right)^0=1\\\\for\ n=2\\\\\left(\dfrac{1}{5}\right)^{2-1}=\left(\dfrac{1}{5}\right)^1=\dfrac{1}{5}\\\\for\ n=3\\\\\left(\dfrac{1}{5}\right)^{3-1}=\left(\dfrac{1}{5}\right)^2=\dfrac{1}{25}\\\\for\ n=4\\\\\left(\dfrac{1}{5}\right)^{4-1}=\left(\dfrac{1}{5}\right)^3=\dfrac{1}{125}$

$\sum\limits_{n=1}^4\left(\dfrac{1}{5}\right)^{n-1}=1+\dfrac{1}{5}+\dfrac{1}{25}+\dfrac{1}{125}=\dfrac{125}{125}+\dfrac{25}{125}+\dfrac{5}{125}+\dfrac{1}{125}=\dfrac{156}{125}$

<h3>Method 2:</h3>

$\sum\limits_{n=1}^4\left(\dfrac{1}{5}\right)^{n-1}\to a_n=\left(\dfrac{1}{5}\right)^{n-1}\\\\\text{The formula of a sum of terms of a geometric series:}\\\\S_n=a_1\cdot\dfrac{1-r^n}{1-r}\\\\r-\text{common ratio}\to r=\dfrac{a_{n+1}}{a_n}\\\\a_{n+1}=\left(\dfrac{1}{5}\right)^{n+1-1}=\left(\dfrac{1}{5}\right)^n\\\\r=\dfrac{\left(\frac{1}{5}\right)^n}{\left(\frac{1}{5}\right)^{n-1}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\r=\left(\dfrac{1}{5}\right)^{n-(n-1)}=\left(\dfrac{1}{5}\right)^{n-n+1}=\left(\dfrac{1}{5}\right)^1=\dfrac{1}{5}$

$a_1=\left(\dfrac{1}{5}\right)^{1-1}=\left(\dfrac{1}{5}\right)^0=1$

$\text{Substitute}\ a_1=1,\ n=4,\ r=\dfrac{1}{5}:\\\\S_4=1\cdot\dfrac{1-\left(\frac{1}{5}\right)^4}{1-\frac{1}{5}}=\dfrac{1-\frac{1}{625}}{\frac{4}{5}}=\dfrac{624}{625}\cdot\dfrac{5}{4}=\dfrac{156}{125}$

5 0

4 years ago

Okay I told me it was two plus two please

nignag [31]

two plus two is four

2+2=4

8 0

3 years ago

Ciaran scores 76% work out 76% of 75 marks <br><br> Help pls

dlinn [17]

To get 76% of 75 you turn the fraction to a decimal, then multiply it to the number. 76% as a decimal us 0.76 and 0.76 * 75 = 57

So, Ciaran got 57 out of 75 questions right.

3 0

4 years ago

Which equation matches the graph?​

Which equation matches the graph?