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2 years ago

The sum of two numbers is 180. one number is 5 times the other

Mathematics

2 answers:

stepan [7]2 years ago

8 0

30 & 150. 150 is five times 30, and 150+30=180

Vlada [557]2 years ago

7 0

Let 2 numbers be x and y then

x + y = 180 and
y = 5x

plug y = 5x into the first equation:-

x + 5x = 180

x = 30

y = 180-30 = 150

The 2 numbers are 30 and 150

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3n^2=6-17n I need Vertex form please.

nasty-shy [4]

Answer:

3( n + $\frac{17}{6}$ )² - $\frac{361}{12}$ = 0

Step-by-step explanation:

3n² = 6 - 17n ⇔ 3n² + 17n - 6 = 0

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3( n + $\frac{17}{6}$ )² - 3 × $\frac{289}{36}$ - 6 = 0

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2 years ago

Which expression is equivalent to -3x + 9?

Olenka [21]

Answer:

Step-by-step explanation:

You use the distributive Property

-3(x-3)

-3x+9

4 0

3 years ago

Read 2 more answers

Use the multiplication rule to find the probability that the first four guesses are wrong and the fifth is correct. That is, fin

BabaBlast [244]

Complete question is;

Multiple-choice questions each have 5 possible answers, one of which is correct. Assume that you guess the answers to 5 such questions.

Use the multiplication rule to find the probability that the first four guesses are wrong and the fifth is correct. That is, find P(WWWWC), where C denotes a correct answer and W denotes a wrong answer.

P(WWWWC) =

Answer:

P(WWWWC) = 0.0819

Step-by-step explanation:

We are told that each question has 5 possible answers and only 1 is correct. Thus, the probability of getting the right answer in any question is =

(number of correct choices)/(total number of choices) = 1/5

Meanwhile,since only 1 of the possible answers is correct, then there will be 4 incorrect answers. Thus, the probability of choosing the wrong answer would be;

(number of incorrect choices)/(total number of choices) = 4/5

Now, we want to find the probability of getting the 1st 4 guesses wrong and the 5th one correct. To do this we will simply multiply the probabilities of each individual event by each other.

Thus;

P(WWWWC) = (4/5) × (4/5) × (4/5) × (4/5) × (1/5) = 256/3125 ≈ 0.0819

P(WWWWC) = 0.0819

4 0

3 years ago

A company wants to select 1 project from a set of 4 possible projects. Which of the following constraints ensures that only 1 wi

Elza [17]

Given:

A company wants to select 1 project from a set of 4 possible projects.

Consider the options are:

a. $X_1+X_2+X_3+X_4=1$

b. $X_1+X_2+X_3+X_4\leq 1$

c. $X_1+X_2+X_3+X_4\geq 1$

d. $X_1+X_2+X_3+X_4\geq 0$

To find:

The constraints that ensures only 1 will be selected.

Solution:

It is given that the company wants to select 1 project from a set of 4 possible projects. It means the sum of selected projects must be equal to 1.

$X_1+X_2+X_3+X_4=1$

Therefore, the correct option is (a).

8 0

2 years ago

NEED HELP NOW!!!

Amiraneli [1.4K]

D.

Explanation:

a landscape of farmland bisected by long straight roads"

divide into two parts.

hope I help you ☺️❤️

:) :>

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2 years ago