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olganol [36]
3 years ago
10

What is the area of this figure?​

Mathematics
1 answer:
timurjin [86]3 years ago
6 0

Answer:

252 inches squared is the answer

Step-by-step explanation:

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Circumference = 2πR = 2×3.14×6.5 = 40.82m
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lora16 [44]

Answer:

Option C. -3x^2-13x-5

Step-by-step explanation:

we know that

To find how much greater is the area of room A than the area of room B. subtract the area of room B from the area of room A

so

(5x^{2}-7x-6)-(8x^{2}+6x-1)\\ \\= (5x^{2}-7x-6)-8x^{2}-6x+1\\ \\=(5x^{2}-8x^{2})+(-7x-6x)+(-6+1)\\ \\=-3x^{2} -13x-5

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Show that the following functions are probability density functions for some value of k and determine k. Then, determine the mea
lord [1]

Answer:

a) 17.5

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c) 13.3

d) 21.51

Step-by-step explanation:

The given function is equal to:

f(x)=kx^2

where

\int\limits^y_0 {kx^{2} } \, =1

where y=23

Clearing k=0.00025

a) Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.00025x^{2} } \, dx =17.5

b)Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2}f(x) } \, dx-17.5^{2}  =\int\limits^y_0 {x^{2} *0.00025x^{2} } \, dx -17.5^{2} =321.82-306.25=15.6

c) The function is equal to:

f(x)=k(1+2x)

\int\limits^y_0 {k(1+2x)} \, =1

where y=20

k=0.0024

Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.0024(1+2x)} \, dx =13.3

d) Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2} f(x)} \, dx -13.3^{2}=\int\limits^y_0 {x^{2} *0.0024(1+2x)} \, dx-13.3^{2}   =198.4-176.89=21.51

8 0
3 years ago
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