Question

The solution to this system of equations lies between the x-values -2 and -1.5. At which x-value are the two equations approximately equal?
y=1/(x+2)
y=x^2+2

A) -1.5
B) -1.6
C) -1.7
D) -1.8

Answer 1

Answer:

x = -1.8  two equations approximately equal.

Step-by-step explanation:

Given : y = $\frac{1}{(x+2)}$ ,y =$y = x^{2} +2$

To find : which x-value are the two equations approximately equal.

Solution  : We have given that

y = $\frac{1}{(x+2)}$ -----( equation 1)

$y = x^{2} +2$------( equation 2).

Plug the of equation 2 in 1

$x^{2} +2$ =  $\frac{1}{(x+2)}$.

$x^{2}(x+2) +2(x+2)$ = 1.

x³+2x² +2x+4 = 1

On subtracting 1 both sides.

x³+2x² +2x+3 = 0

For x = -1.8

Therefore,  x = -1.8  two equations approximately equal.

Answer 2

D) -1.8
$-1.8$