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Elenna [48]
3 years ago
9

The solution to this system of equations lies between the x-values -2 and -1.5. At which x-value are the two equations approxima

tely equal?
y=1/(x+2)
y=x^2+2

A) -1.5
B) -1.6
C) -1.7
D) -1.8
Mathematics
2 answers:
igor_vitrenko [27]3 years ago
7 0

Answer:

x = -1.8  two equations approximately equal.

Step-by-step explanation:

Given : y = \frac{1}{(x+2)} ,y =y = x^{2} +2

To find : which x-value are the two equations approximately equal.

Solution  : We have given that

y = \frac{1}{(x+2)} -----( equation 1)

y = x^{2} +2------( equation 2).

Plug the of equation 2 in 1

x^{2} +2 =  \frac{1}{(x+2)}.

x^{2}(x+2) +2(x+2) = 1.

x³+2x² +2x+4 = 1

On subtracting 1 both sides.

x³+2x² +2x+3 = 0

For x = -1.8

Therefore,  x = -1.8  two equations approximately equal.

katovenus [111]3 years ago
6 0
D) -1.8
-1.8
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