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mafiozo [28]
3 years ago
12

Substitute!

Mathematics
1 answer:
Cloud [144]3 years ago
7 0
1. 4x(-4)x(-5)= 80
2. 5x(-4)-2x(-5) = -10
3. [-4x(-5)]x2= 40
4. -4x2x(-5)= -13
5. 4x(-4)x(-5)x2= 160
6. 3x(-4)x(-5)-5x(-5)= 85
7. -4x(-5)<span>÷2= 10
8. 3x(-4)x2</span><span>÷4= -6
9. 5x(-5)-(-4)x2= -17

I wasn't sure what the space were so I thought they were mistakes and did the problems as if they were not there but if they were meant to be there then tell me what they were meant to be and I will fix it (If there is no spaces on yours then you are probably thinking that I am going crazy)

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Solve<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3x%20%2B%204%7D%7B2%7D%20%20%3D%209.5" id="TexFormula1" title=" \frac{3x
ELEN [110]
Answer: 5

Step by step:

(3x+4)/2 = 9.5
3x+4 = 9.5*2
3x+4 = 19
3x = 19 -4
3x = 15
x = 5

7 0
3 years ago
Read 2 more answers
i need help on math
dolphi86 [110]
X=2
2x-3=-x+3

add three to both sides
add 1x to each side
should be left with 3x=6
divide both sides by 3 to get x alone
your answer then is x=2
7 0
3 years ago
If the two terms of a gemotric sequence are a1=216, and a2=72, which is the third term? a3?
Ierofanga [76]
GEOMETRIC \: \: PROGRESSIONS \\ \\ \\\\Let \: the \: G.P. \: be \: \: A \: , \: Ar \: , \: A {r}^{2} \: ... \\ \\ Where \:first \: term \: is \: \: A \: \: \\ and \: common \: ratio \: is \: \: R \\ \\ Let \: An \: denotes \: the \: \: nth \: term \: of \: \\ the \: given \: Geometric \: Progression \: \\ \\ It \: is \: given \: - \\ \\ A1 \: = \: 72 \\ \\ A2 \: = \: 216 \\ \\ Common \: ratio \: = \: \frac{A2}{A1} = \frac{216}{72} \\ \\ R = 3 \\ \\ A \: = \: 72 \\ \\ A3 \: = \: A {r}^{2} = 72 \times 3 \times 3 \\ \\ \\ Hence \: , \: A3 \: = \: 648 \: \: \: \: \: \: \: Ans.
4 0
3 years ago
Two triangles are similar. The perimeter of the smaller one is 16. The ratio of the corresponding sides is 2:5. The sides of the
Eddi Din [679]

Answer:

Perimeter of larger triangle is 40.

Step-by-step explanation:

Given:

Perimeter of smaller circle = 16

Ratio of corresponding side = 2:5

We need to find the perimeter of the larger triangle.

Solution:

Let the perimeter of the larger triangle be 'x'.

Therefore by theorem which states that;

" When a triangle have scale factor a:b then the ratio of the perimeters is a:b".

Here Ratio is 2:5, so we can say by theorem, Ratio of perimeters is 2:5

framing in equation form we get;

\frac{\textrm{Perimeter of smaller triangle}}{\textrm{Perimeter of Larger triangle}}=\frac{2}{5}

Substituting the values we get;

\frac{16}{x}=\frac{2}{5}

By Cross multiplication we get;

16\times 5=2x\\\\80=2x

Dividing both side by 2 we get;

\frac{80}{2}=\frac{2x}{2}\\\\x=40

Hence Perimeter of larger triangle is 40.

7 0
3 years ago
Write this number in word form. 284,028
natali 33 [55]
Two hundred eighty-four thousand, twenty-eight.
7 0
3 years ago
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