Suppose that many large samples are taken from a population and that the sample proportions are normally distributed, with a mea
n of 0.22 and a standard error of 0.029. What is the 95% confidence interval?
by Anohaptay 12 minutes ago
1 answer:
Answer:
[0.16316 , 0.27684]
Step-by-step explanation:
0.22 +/- 1.96(0.029)
0.22 +/- 0.05684
[0.16316 , 0.27684]
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I’m not sure but I added them up & combined like terms & got x=17.
Step-by-step explanation:
p/2 = 3/4 + p/3
p/2 - p/3 = 3/4
(3p - 2p )/6 = 3/4
p/6 = 3/4
multiply both sides by 6
p = 3×6/4
=18/4
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