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grigory [225]
4 years ago
11

Which ordered pair is located in Quadrant 11?

Mathematics
2 answers:
liraira [26]4 years ago
7 0

Answer:

(-1,2.5) is in quadrant 2.

Step-by-step explanation:

I graphed all of the point on the graph below to show you which points were in quadrant 2. The only point is (-1,2.5)

nika2105 [10]4 years ago
6 0

Answer:

(-1.2, 5)

Step-by-step explanation:

(-1.2, 5) is in Quadrant II.  Here x = -1.2 (which lies to the left of the y-axis) and 5 lies above the x-axis.

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Gracie earns $7 for each car she washes. she always saves $25 of her weekly earnings. this week, she wants to have at least $65
nata0808 [166]
65 divided by 7 is approximently 9, and 25 divided by 7 is approximently 3, so 9 plus 3 is 12, so Gracie must wash 12 cars to earn enough money to save 25 and spend 65!
7 0
3 years ago
Solve the equation: w^2+7w+12=0
polet [3.4K]
Hi there!
We are given the equation w² + 7w + 12 = 0, and we are told to solve it. Well, we can first take all the factors of 12 -
1 12
2 6
3  4
Now, take the sum of each factor pair -
1, 12 = 13
2, 6 = 8
3, 4 = 7
Find which factor pair adds up to 7, and we can see that 3 and 4 add up to seven, while also having a product of 12. Therefore, since the whole equation has addition signs, we can factor the equation w² + 7w + 12 into (w + 3)(w + 4) = 0. Next, using the Zero Product Property, we can set each term to zero.
w + 3 = 0
w = -3

w + 4 = 0
w = -4
Therefore, the solution to the equation w² + 7w + 12 = 0 is w = -3, -4. Hope this helped and have a great day!
7 0
3 years ago
What is the horizontal asymptote for y(t) for the differential equation dy dt equals the product of 2 times y and the quantity 1
marta [7]
First, we need to solve the differential equation.
\frac{d}{dt}\left(y\right)=2y\left(1-\frac{y}{8}\right)
This a separable ODE. We can rewrite it like this:
-\frac{4}{y^2-8y}{dy}=dt
Now we integrate both sides.
\int \:-\frac{4}{y^2-8y}dy=\int \:dt
We get:
\frac{1}{2}\ln \left|\frac{y-4}{4}+1\right|-\frac{1}{2}\ln \left|\frac{y-4}{4}-1\right|=t+c_1
When we solve for y we get our solution:
y=\frac{8e^{c_1+2t}}{e^{c_1+2t}-1}
To find out if we have any horizontal asymptotes we must find the limits as x goes to infinity and minus infinity. 
It is easy to see that when x goes to minus infinity our function goes to zero.
When x goes to plus infinity we have the following:
$$\lim_{x\to\infty} f(x)$$=y=\frac{8e^{c_1+\infty}}{e^{c_1+\infty}-1} = 8
When you are calculating limits like this you always look at the fastest growing function in denominator and numerator and then act like they are constants. 
So our asymptote is at y=8.

3 0
3 years ago
Hector and his brother, Lee, collect toy cars. Hector has c cars, where c > 10. Lee has 35% more cars than Hector, but he don
son4ous [18]

Answer:

b) c + 0.35c − 10

Step-by-step explanation:

3 0
3 years ago
7/10 divided by -2/7
Tpy6a [65]

Answer:

1/20

Step-by-step explanation:

hope this helps

6 0
2 years ago
Read 2 more answers
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