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grigory [225]
3 years ago
11

Which ordered pair is located in Quadrant 11?

Mathematics
2 answers:
liraira [26]3 years ago
7 0

Answer:

(-1,2.5) is in quadrant 2.

Step-by-step explanation:

I graphed all of the point on the graph below to show you which points were in quadrant 2. The only point is (-1,2.5)

nika2105 [10]3 years ago
6 0

Answer:

(-1.2, 5)

Step-by-step explanation:

(-1.2, 5) is in Quadrant II.  Here x = -1.2 (which lies to the left of the y-axis) and 5 lies above the x-axis.

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A package weighs 80 ounces. What is the weight of the package in pounds?
Degger [83]

Answer:

5

Step-by-step explanation:

1 ounce = 0.0625

0.0625 x 80 = 5

3 0
2 years ago
Evaluate the expression 3(7 + 4)2 − 14 ÷ 7. (5 points)
Kitty [74]
<span>3(7 + 4)2 − 14 ÷ 7

First do the parenthesis

7 + 4 = 11

so the question looks like: 3(11)2 - 14/7

Then multiply 3, 11, and 2 together

3 x 11 x 2 = 66

66 - 14/7

14/7 equals to 2

66 - 2 

Then just simplify

66 - 2 = 64

64 is your answer

hope this helps</span>
3 0
3 years ago
Read 2 more answers
How do I solve this problem
guapka [62]
You first subtract 1/5 from both sides
3/4-1/5 = 11/20 
3/2x=11/20

now you multiply 2/3 on both sides since you have to get x

11/20 * 2/3 
x = 11/30




3 0
3 years ago
Find values of x and y for which ABCD must be a parallelogram. The diagram is not drawn to scale.
Arturiano [62]
ANSWER
x=4, y=8

EXPLANATION

If ABCD is a parallelogram, then

line AB is parallel to line DC .

This means that,

(x + 2) \degree
and

(2x - 2) \degree
are alternating angles.

Alternate angles are congruent.

This implies that,

2x - 2 = x + 2

We group like terms to obtain,

2x - x = 2 + 2

This simplifies to,

x = 4

Also, if ABCD is a parallelogram then,

BC is parallel to AD. This means that,

5y - 8 = y + 24

We group like terms to get,

5y - y = 24 + 8

This simplifies to,

4y = 32

We divide both side by 4 to get,

y = 8
6 0
3 years ago
Read 2 more answers
Find the area of the rug. DO NOT ROUND. <br><br> what is the area?
Neporo4naja [7]

Answer:

28.26 ft²

Explanation:

\sf area \ of  \ circle    = \pi r^2

<u>Here given diameter: 6 ft</u>

radius: d/2 = 6/2 = 3 ft

========

area of rug:

\dashrightarrow \  \pi (3)^2

\dashrightarrow \  9\pi

\dashrightarrow \  9(3.14)

\dashrightarrow \  28.26 \ ft^2

7 0
2 years ago
Read 2 more answers
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