6/1 ÷ 3/4
= 6/1 × 4/3
= 24/3
= 8
Alternate interior angles on parallel lines via the parallel postulate gives you the angle supplementary to x = 120°, so x = 60°. alternate interior angles on 70° via the parallel postulate gives you y = 70°
Here we need to find fog and gof, and they must be equal to x .
Let's check out fog
fog = f(g(x))

Substituting the value of g(x) in f(x) for x, we will get

Domain
Here the input function is g(x), and the denominator should not be 0. So x should not be zero. Therefore, domain is

Now let's check gof
gof = g(f(x))
Here we need to insert f(x) in g(x) for x, and on doing that , we will get

Domain
Here the input function is f(x), and denominator should not be zero.
SO domain is

Since fog = gof =x, so the given function are inverses of each other .
1.082 x 10^8
1.496 x 10^8
2.279 x 10^8
7.784 x 10^8
1.4 x 10^9
2.87 x 10^9
4.5 x 10^9
5.9 x 10^9
Hope it helps!
Answer:
y = 2 (x + seven-halves) squared minus one-fourth [y =
]
Step-by-step explanation:
We know that,
vertex form is y = a(x-h)² + k
vertex is (h, k)
Now,
Given that the equation is -
y = (x+3)² + (x+4)²
= x² + 3² + 2×3×x + x² + 4² + 2×4×x
= x² + 9 + 6x + x² + 16 + 8x
= 2x² + 14x + 25
= 
= 
= 
= 
∴ we get
The vertex form is -
y = 
So,
The correct option is - y = 2 (x + seven-halves) squared minus one-fourth (y =
)