Answer:
The correct answer choice would be:
C (Same-Side Interior Angles Theorem)
Hope this helps! :)
Answer:
a
Step-by-step explanation:
7 times a number will add up to 210

On top: (-2)³ = -2 × -2 × -2 = -8
(x²)³ = x^6 (the exponents multiply)
and of course, (y)³ = y³
On the bottom: (xy²z)² = x² y^4 z²
(-yz)² = y²z²
Multiplying these together, the exponents add and we get x² y^6 z^4.

So, your reasoning is correct for what you have so far.
Your next step would be cancelling shared factors from the top and bottom.
Just like with regular fractions, if the numerator and denominator are divisible by the same number, you can divide them by it to simplify. (ex: 4/6 = 2/3)
Well, x^6 and x^2 are both divisible by x^2, right?
We can also cancel the y^3.
It might help to visualise the factors like this:

Once you've cancelled out x² and y³ from each, you're left with
Answer:
(a) 512 dimes
(b)
(c) 9.22337 x 10¹⁸ dimes
(d) 9.22337 x 10¹² km
(e) roughly 61,489.13 times longer than the distance from the earth to the sun.
Step-by-step explanation:
b. Starting with 1 dime in the first square, if the number of dimes per each square is the double of the previous square, the general equation for the number of dimes in each square 'n' can be found by:

a. On the 10th square:

c. On the 64th square:

d. If a dime is 1 mm thick, the 64th pile will be:

e. The ratio between the height of the last pile (h) to the distance from the earth to the sun is:

The height of the last pile is roughly 61,489.13 times longer than the distance from the earth to the sun.
Answer: The theoretical probability of the coin landing heads up is 0.7
Step-by-step explanation:
Hi, to answer this question we simply have to divide the number of times that the coin lands heads up (42 times) by the number of times that the coin was flipped:
Mathematically speaking:
42 /60 = 0.7 (decimal form)
The theoretical probability of the coin landing heads up is 0.7
For the or percentage form we simply multiply the result by 100:
0.7 (100) = 70%
Feel free to ask for more if needed or if you did not understand something.