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4 years ago

8

Solve the fórmula d= rt for t

2 answers:

Gala2k [10]4 years ago

6 0

Answer:

d/r = t

Step-by-step explanation:

d = r * t

d/r = t

dimaraw [331]4 years ago

4 0

Answer:

d/r = t

Step-by-step explanation:

d = r * t

d/r = t

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Beth wants to buy Christmas lights to decorate her new home. At various stores, Beth found lights priced from $6.99 a strand to

Monica [59]

Answer:

Christmas lights are price based shopping products

Step-by-step explanation:

From the question we understand that, Beth bought as many cheapest lights as possible. This means that she places value over quantity than quality.

The above is an illustration of price based shopping products where customers (in this case, Beth) see all products (in this case, Christmas lights) as similar products, irrespective of their different qualities (after all, they all light Christmas trees).

Because of this, the customer will opt for least expensive items, leaving the more expensive items.

8 0

3 years ago

Someone explain!! geometry

ikadub [295]

Step-by-step explanation:

sin 0 = opposite ÷ hypothenus

sin 0 = 3 / 5

3 / 5 = x / 15

5 × n = 15

n = 3

x = 3 × 3 = 9

y = use pythagoras

= 12

tan 0 = opposite ÷ adjacent

tan 0 = 9/12

4 0

4 years ago

Write (8a^-3)^-2/3 in a simplest form.

MrRa [10]

For this case we have the following expression:

$(8a^{-3})^{-\frac{2}{3}}$

For power properties we have:

$(8^{-\frac{2}{3}} a^{-3*-\frac{2}{3}})$

Rewriting the exponents of the expression we have:

$(8^{-\frac{2}{3}} a^{3*\frac{2}{3}})$

$(8^{-\frac{2}{3}} a^2)$

$(\frac{1}{8^{\frac{2}{3}}} a^2)$

Using the cubic root we have:

$(\frac{1}{\sqrt[3]{8^2}} a^2)$

$(\frac{1}{\sqrt[3]{64}} a^2)$

$(\frac{1}{\sqrt[3]{4^3}} a^2)$

Simplifying the expression we have:

$(\frac{1}{4} a^2)$

Answer:

The equivalent expression is given by:

$(\frac{1}{4} a^2)$

8 0

3 years ago

Read 2 more answers

How much times is 4000 more than 400

Julli [10]

Answer:

4000 is 10 times greater than 400.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

An antenna stands on top of a 160 ft. building. From a point on the ground 118 ft. from the base of the building, the angle of e

uysha [10]

Answer: the height of the antenna is 21

Step-by-step explanation:

The diagram illustrating the scenario is shown in the attached photo. A right angle triangle ABC is formed.

Let x represent the height of the antenna. Therefore, the height of the building and the antenna would be (160 + x) feet

We would determine (160 + x) feet by applying the tangent trigonometric ratio which is expressed as

Tan θ = opposite side/adjacent side

Therefore

Tan 58 = (160 + x)/118

160 + x = 118tan58

160 + x = 118 × 1.6003

160 + x = 188.8354

x = 188.8354 - 160

x = 20.8354

Approximately 21 feet

6 0

4 years ago