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3 years ago

The 1903 Muller v. Oregon decision upheld

2 answers:

3 0

The answer to your question is : A. limited work hours for women

Think about it this way:
Can't be D because 1919 was when women had the right to vote
Can't be B because that wouldn't be fair
Can't be C because that just doesn't make sense

faltersainse [42]3 years ago

3 0

<span>The case upheld Oregon state restrictions on the working hours of women. Just as stated in answer A.

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What is the least common multiple of 2,6 and 15?

Alex

Answer:

LCM of 6 and 15 by Listing Multiples

Step 2: The common multiples from the multiples of 6 and 15 are 30, 60, . . . Step 3: The smallest common multiple of 6 and 15 is 30.

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3 years ago

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The Jackson's are taking out a $35,000 loan to remodel their home. The tables below show the rates for a 1-year and a 5-year loa

Vladimir [108]

Answer:

have a good day :)

Step-by-step explanation:

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3 years ago

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If a simple harmonic motion is described by x = 3 cos(πt), starting from t = 0 s, what is the first occurrence of a value of t f

poizon [28]

Answer:

The first occurence of t for which x = 0 is t = 0.5.

Step-by-step explanation:

The harmonic motion is described by the following equation.

$x(t) = 3\cos{\pi t}$

What is the first occurrence of a value of t for which x = 0?

This is t when $x(t) = 0$ . So

$x(t) = 3\cos{\pi t}$

$3\cos{\pi t} = 0$

$\cos{\pi t} = \frac{0}{3}$

$\cos{\pi t} = 0$

The inverse of the cosine is the arcosine. So we apply the arcosine function to both sides of the equality.

$\arccos{\cos{\pi t}} = \arccos{0}$

$\pi t = \frac{\pi}{2}$

$t = \frac{\pi}{2 \pi}$

$t = \frac{1}{2}$

$t = 0.5$

The first occurence of t for which x = 0 is t = 0.5.

3 0

3 years ago

Factor the following expression. Simplify your answer.<br> 3s(s - 1)^1/3 + 2(s - 1)^4/3

denis23 [38]

Answer:

Step-by-step explanation:

$3s\sqrt[3]{s-1} + 2 \sqrt[4/3]{s-1} =\\3s\sqrt[3]{s-1} + 2 \sqrt[1/3]{(s-1)^4} =\\3s\sqrt[3]{s-1} + 2 (s-1)\sqrt[1/3]{s-1} =\\\sqrt[3]{s-1}*(3s + 2 (s-1)) =\\\sqrt[3]{s-1}*(3s + 2s-2)) =\\\sqrt[3]{s-1}*(5s -2) \\$

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2 years ago

Read 2 more answers

What is the length of leg s of the triangle below?

vekshin1

Answer:

4 units

Step-by-step explanation:

Let ABC be isosceles right angled ∆ right angled at B

By Pythagoras theorem,

AC² = AB² + BC²

(√32)² = 4² + s²

32 = 16 + s²

s² = 32 - 16

s² = 16

s = √16

s = 4 units.

Therefore s = 4 units

Hope it helps...

6 0

3 years ago