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3 years ago

Mark pulled weeds from the garden for 10 more minutes than Ted.

Mathematics

2 answers:

Gwar [14]3 years ago

5 0

B because 10p means 10 × p

Ne4ueva [31]3 years ago

5 0

D.
Mark pulled weeds for 10 MORE minutes than Ted. This indicates addition. So if p stands for Ted's minutes weeding, then 10+p

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The price of a house is originally listed at $205,000. The owners are having a hard time selling it and decide to reduce the pri

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Answer:

The percentage decrease is 27%

Step-by-step explanation:

To find the percent decrease, first find the difference in the two costs.

$205,000 - $149,650 = $55,350

Now divide that number by the original cost.

$55,350/$205,000 = 27%

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3 years ago

What is the domain and range of the relation [(1, -8), (-7,8), (-3, 7). (-3, -5]?

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Step-by-step explanation:

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3 years ago

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3 years ago

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11. Evaluate: f(x) = x^2 - 2x + 1,

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Answer:

Step-by-step explanation:

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3 years ago

You are working in a primary care office. Flu season is starting. For the sake of public health, it is critical to diagnose peop

Aleksandr-060686 [28]

Answer:

E. 0.11

Step-by-step explanation:

We have these following probabilities:

A 10% probability that a person has the flu.

A 90% probability that a person does not have the flu, just a cold.

If a person has the flu, a 99% probability of having a runny nose.

If a person just has a cold, a 90% probability of having a runny nose.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem, we have that:

What is the probability that a person has the flu, given that she has a runny nose?

P(B) is the probability that a person has the flu. So P(B) = 0.1.

P(A/B) is the probability that a person has a runny nose, given that she has the flu. So P(A/B) = 0.99.

P(A) is the probability that a person has a runny nose. It is 0.99 of 0.1 and 0.90 of 0.90. So

$P(A) = 0.99*0.1 + 0.9*0.9 = 0.909$

What is the probability that this person has the flu?

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.1*0.99}{0.909} = 0.1089 = 0.11$

The correct answer is:

E. 0.11

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3 years ago