Answer:
Graphs A and B
Step-by-step explanation:
Graphs A & B are using x-values 1-6 and stop there, which is what the domain is trying to find. Though, for the other graphs, these graphs are rather starting at 1 via the domain, while not going up to 6 on the domain.
The area of this figure is, the area of this figure.
Answer:

Step-by-step explanation:
Given
Function; 
Required
Find an equation perpendicular to the given function if it passes through (-3,9)
First, we need to determine the slope of: 
The slope intercept of an equation is in form;

<em>Where m represent the slope</em>
Comparing
to
;
We'll have that

Going from there; we need to calculate the slope of the parallel line
The condition for parallel line is;

Substitute 

Divide both sides by -2


The point slope form of a line is;

Where
and 
becomes

Open the inner bracket

<em>Hence, the point slope form of the perpendicular line is: </em>
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1. 3 1/4
2.9 1/2 hope it helped
The quotient is 5x+3 and the remainder is 5/x-1
my work is attached below