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qwelly [4]
4 years ago
14

A line contains the points (–4, 5) and (3, –9). Write the equation of the line using slope-intercept form.

Mathematics
1 answer:
Galina-37 [17]4 years ago
4 0
(-4,5)(3,-9)
slope = (-9 - 5) / (3 - (-4) = -14 / (3 + 4) = -14/7 = -2

y = mx + b
slope(m) = -2
use either of ur points...(-4,5)...x = -4 and y = 5
now we sub and find b, the y int
5 = -2(-4) + b
5 = 8 + b
5 - 8 = b
-3 = b

so ur equation is : y = -2x + (-3) which can be written as : y = -2x - 3
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Answer:

9330

Step-by-step explanation:

6 boys

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Which of these numbers has the highest value? -22, 0.0099, 0, -1, (-1)
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In the triangle shown above m∠B = 114°, m∠C = 22°, and b = 12 in. What is the approximate length of side a? A. 15.78 in B. 9.12
Elena L [17]

The approximate length of side a is 9.12 in. The correct option is B. 9.12 in

<h3>Law of Sines </h3>

From the question, we are to determine the approximate length of side a

From the given information, we have that

m∠B = 114°, m∠C = 22°

Thus,

m∠A = 180° - (114° + 22°)

m∠A = 180° - 136°

m∠A = 44°

Now,

From the law of sines, we have that

a/sinA = b/sinB

Then,

a/sin44° = 12/sin114°

a = (12 ×sin44°)/sin114°

a = 9.12 in

Hence, the approximate length of side a is 9.12 in. The correct option is B. 9.12 in

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4 0
1 year ago
What is the volume of the cone? cone v = one-third b h startfraction 70 over 3 endfraction pi centimeters cubed startfraction 14
Bas_tet [7]

Using the assumed values, the volume of the cone is V = \frac {250}3\pi

<h3>How to determine the volume of the cone?</h3>

The volume of a cone is calculated using:

V = \frac 13\pi r^2h

The parameters are not given.

So, we use the following assumed values

Radius, r = 5

Height, h =10

Using the assumed values, we have:

V = \frac 13\pi * 5^2 * 10

Evaluate the product

V = \frac {250}3\pi

Hence, using the assumed values, the volume of the cone is V = \frac {250}3\pi

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7 0
2 years ago
Solve the system by elimination <br> 2x+6y= -12 <br> 5x-5y= -10
kvv77 [185]
First thing you should do is reduce coefficients.

1st equation has all multiples of '2'. Divide by 2
---> x +3y = -6

2nd equation has multiples of 5. Divide by 5.
---> x - y = 2

Now elimination part is easier. 
Eliminate 'x' variable by subtracting 2nd equation from 1st.

   x + 3y = -6
-(x  - y = 2)
----------------------
       4y  = -8

Solve for 'y'
4y = -8

y = (-8)/4 = -2


Substitute value for 'y' back into 2nd equation:
x - (-2) = 2
x + 2 = 2
x = 0

Solution to system is:
x=0, y =-2

5 0
4 years ago
Read 2 more answers
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