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dem82 [27]
3 years ago
7

A simple random sample of size n is drawn from a normally distributed population, and the mean of the sample is x Overbar, while

the standard deviation is s. What is the 99% confidence interval for the population mean? Use the table below to help you answer the question.

Mathematics
2 answers:
Zarrin [17]3 years ago
8 0

Answer:

it is actually B..

Step-by-step explanation:

rewona [7]3 years ago
5 1

Answer:

CI = x ± 2.58 (s / √n)

Step-by-step explanation:

The confidence interval is the mean plus or minus the margin of error.  The margin of error is the critical value times the standard error.  For a normal distribution, the critical value is the z-score at the given confidence level.  The standard error is the standard deviation divided by the square root of the sample size.

CI = x ± z (s / √n)

At 99% confidence, z = 2.58.

CI = x ± 2.58 (s / √n)

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