Answer:
3000 bags
Step-by-step explanation:
In this case we must apply the formula of the mean, which would be the sum of the values divided by the amount of data is the mean:
m = (a1 + a2 ... an) / n
In this case we know the mean, we must know the 1987 data, therefore:
Let x be the number of bags sold in 1987, replacing in the previous equation:
2100 = (1800 + 1500 + x) / 3
2100 * 3 = 3300 + x
x = 6300 - 3300
x = 3000
Therefore, for the average to be a total of 2100 bags in those 3 years, the amount of bag sold in 1987 must have been 3000 bags
What is the interquartile range for this data set? 9, 17, 3, 26, 9, 15, 7, 20, 5, 12, 22
stepan [7]
23 because you subtract your highest number with your lowest number
So the question ask to find the displacement vector and the distance from the submarine to the boat. Base on my calculation the displacement value of the given data you give is <(5-3),(1-4)(-5-0)>. I hope you are satisfied with my answer and feel free to ask for more
Im gonna asume you mean side, so 1 foot = 12 inches (:
