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Sedaia [141]
3 years ago
7

The amount of a sample remaining after t days is given by the equation mc001-1.jpg, where A is the initial amount of the sample

and h is the half-life, in days, of the substance. A scientist has a 10-mg sample of a radioactive isotope. The isotope has a half-life of 8 days. After 16 days, how much of the radioactive isotope remains? 2.0 mg 2.5 mg 5.7 mg 7.1 mg
Mathematics
2 answers:
vichka [17]3 years ago
8 0

Answer:

b. 2.5 mg

just took the test on edge

kherson [118]3 years ago
5 0

P(t)= A(1/2)^(t/h)

P(t)=10(1/2)^(16/8)

<em>(1/2)^(16/8) =.25</em>

P(t)=10(.25)

P(t)=2.5

Therefore the answer is B. 2.5mg.

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(x+3)²(65)=x(6)<br>Solve using quadric formula​
Angelina_Jolie [31]

Step 1: Simplify both sides of the equation.

  • 65x²+390x+585=6x

Step 2: Subtract 6x from both sides.

  • 65x²+390x+585−6x=6x−6x
  • 65x²+384x+585=0

For this equation: a=65, b=384, c=585

  • 65x²+384x+585=0

Step 3: Use quadratic formula with a=65, b=384, c=585

  • x=−b±√b2−4ac/2a
  • x=−(384)±√(384)2−4(65)(585)/
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Therefore, There are no real solutions.

6 0
3 years ago
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Maurice earns a commission of 6,048 from the sale of a Lexus, priced at $50,400. What is Maurice's commission rate?
Nutka1998 [239]

Answer:

commission rate of Maurice is 12%

Step-by-step explanation:

Maurice earns commission = $6,048

Lexus priced at = $50,400

Maurice's commission rate =

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hence the commission rate of Maurice is 12%

8 0
3 years ago
Condense the expression to the logarithm of a single quantity.
kherson [118]

\dfrac 12 \log_3 x - 2\log_3 (y +8)\\ \\=\log_3 x^{\tfrac 12}- \log_3(y+8)^2~~~~~~~~~~~~~~~~~~;[\log_b m^n = n \log_b m]\\\\=\log_3 \left( \dfrac {x^{\tfrac 12}}{y+8)^2} \right)~~~~~~~~~~~~~~~~~~~~~~~~;\left[\log_b \left( \dfrac mn \right) = \log_b m - \log_b n \right]

3 0
2 years ago
If a square has a side length of 5cm what would the area be
EastWind [94]

Answer:

25 cm squared

Step-by-step explanation:

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4 years ago
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