All categories

3 years ago

Graph the function f(x) =( square root of x) -6

Mathematics

1 answer:

nikklg [1K]3 years ago

6 0

Answer:

This is the graph. It is a normal square root function, but translated down 6 units.

You might be interested in

Which of the binomials below is a factor of this trinomial? x^2 + 3x - 4A. x+4B. x+8C. x-4D. x^2+4

Usimov [2.4K]

Given:

The equation is:

$x^2+3x-4$

Find-:

Binomials factor of the equation

Explanation-:

The quadratic equation,

$x^2+3x-4$

Solve for factor

$\begin{gathered} =x^2+3x-4 \\ \\ =x^2+4x-x-4 \\ \end{gathered}$

Then the factor is:

$\begin{gathered} =x^2+4x-x-4 \\ \\ =x(x+4)-1(x+4) \\ \\ =(x+4)(x-1) \end{gathered}$

So, the factor is x + 4

6 0

11 months ago

3643 in scientific notation

Lesechka [4]

3.643 x 10^3
move the decimal in between the first and second number
However many times you move the decimal, that is you exponent.

6 0

3 years ago

Carlos has 7 1/2 acres of farmland. He uses 1/3 of the acres to graze animals and 1/5 of the acres to grow vegetable. How many a

omeli [17]

8/15 or somthing like that it you might be souposed to solve it diferent than i did

3 0

3 years ago

A 30 gram sample of a substance that's used to sterilize surgical instruments has a k-value of 0.1235. Find the substances half

jok3333 [9.3K]

Answer : The substances half life in days is, 5.6 days.

Step-by-step explanation :

Half life : It is defined as the amount of time taken by a radioactive material to decay to half of its original value.

All radioactive decays follow first order kinetics.

The relation between the half-life and rate constant is:

$k=\frac{0.693}{t_{1/2}}$

where,

k = rate constant = 0.1235 per days

$t_{1/2}$ = half-life

Now put all the given values in the above formula, we get:

$0.1235\text {days}^{-1}=\frac{0.693}{t_{1/2}}$

$t_{1/2}=5.6\text{ days}$

Thus, the substances half life in days is, 5.6 days.

5 0

3 years ago

What equation represents y=2x^2+24x+85 in vertex form

Andrej [43]

Y=a(x-h)^2+k

vertex form is basically completing the square

what you do is
for
y=ax^2+bx+c
1. isolate x terms
y=(ax^2+bx)+c
undistribute a
y=a(x^2+(b/a)x)+c
complete the square by take 1/2 of b/a and squaring it then adding negative and postive inside
y=a(x^2+(b/a)x+(b^2)/(4a^2)-(b^2)/(4a^2))+c
complete square
too messy \
anyway

y=2x^2+24x+85
isolate
y=(2x^2+24x)+85
undistribute
y=2(x^2+12x)+85
1/2 of 12 is 6, 6^2=36
add neagtive and postivie isnde
y=2(x^2+12x+36-36)+85
complete perfect square
y=2((x+6)^2-36)+85
distribute
y=2(x+6)^2-72+85
y=2(x+6)^2+13

vertex form is
y=2(x+6)^2+13

8 0

3 years ago