The set of natural numbers is {1, 2, 3, 4, ...} basically positive whole numbers
The set of whole numbers is {0, 1, 2, 3, ...} which is the set of natural numbers with 0 included
The set of integers is {..., -3, -2, -1, 0, 1, 2, 3, ...} consisting of positive and negative whole numbers, plus zero as well
The set of rational numbers is the set of all fractions of the form a/b where b is not equal to zero. Any whole number, natural number, and integer is also a rational number.
If the number cannot be expressed as a rational number, then it is said to be irrational
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With all that in mind, the answers are "integer" and "rational" as you wrote in the comment section above. The value -25 is in the set {..., -3, -2, -1, 0, 1, 2, 3, ...} which is the set of integers. So we can say that -25 is an integer.
-25 is not a whole number based on the definition I wrote above. The set of whole numbers I wrote above does not include any negative values. This is why -25 is not a natural number either.
We can say that -25 is rational since -25 = -25/1 which is a fraction of integers. Since -25 is rational, it cannot be irrational.
Answer:
I only found out the MPH for 10 mins, it's 4mph. please let me know if this is what your looking for.
Step-by-step explanation:
I divided 6 by 15 and I got .40 then I multiplied 10 and that's how i got my answer.
Answer:
Step-by-step explanation:
If there is a character you cannot type, such as θ, you are better off substituting a different letter, or describing it in words. For example, write it as "sinA" or "sin(theta)"
Never use 0 as a substitute for θ! 0 is a constant with a specific value.
Since the argument of the trig functions is an expression, you should put parentheses around it: sin(2A).
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I used several trigonometric identities for this question:
Double-angle formula for sine: sin(2θ) = 2sinθcosθ
Double-angle formula for tangent: tan(2θ) = 2tanθ/(1-tan²θ)
Quotient identity: tanθ = sinθ/cosθ
Reciprocal identity: secθ = 1/cosθ
Pythagorean identity: 1+tan²θ = sec²θ
2sin(2θ) - tan(2θ) = 0
2sin(2θ) = tan(2θ)
2·2sinθcosθ = 2tanθ/(1-tan²θ)
2sinθcosθ = tanθ/(1-tan²θ)
2sinθcosθ = (sinθ/cosθ ) · 1/(cosθ(1-tan²θ))
2(1-tan²θ) = 1/cos²θ
2(1-tan²θ) = sec²θ
2-2tan²θ) = 1+tan²θ
1 = 3tan²θ
tan²θ = ⅓
tanθ = ±1/√3
θ = 30°, 330°
