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Explanation:
(32)n × 33 × 3n – (33)n/ (315 × 23) = (1/27) = 3(2n+2+n) – (33)n/ (315 × 23) = (1/27) = 3(3n+2)– (33)n/ (315 × 23) = (1/27) = 33n × 32 – 33n/ (315 × 23) = (1/27) = 33n × (32 – 1)/ (315 × 23) = (1/27) = 33n × (9 – 1)/ (315 × 23) = (1/27) = 33n × (8)/ (315 × 23) = (1/27) = 33n × 23/ (315 × 23) = (1/27) = 33n/315 = (1/27) = 33n-15 = (1/27) = 33n-15 = (1/33) = 33n-15 = 3-3
On equating the coefficients, we get
3n -15 = -3 ⇒
3n = -3 + 15
⇒ 3n = 12
⇒ n = 12/3 = 4
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