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qaws [65]
3 years ago
15

What is 81040 divided by 20?

Mathematics
1 answer:
Nitella [24]3 years ago
3 0
\frac{81040}{20}=4052

To check your work do 20 x 4052 which should equal the Original value that you are dividing 

Answer: 4052
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Romashka [77]
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"</span><span>all real numbers between 19 and 54 inclusive" is the range.  Why?  Because in year 3, f(3) = height of tree = 5(3) + 4 = 19 feet.  

In year 10, f(10) = 5(10) + 4 = 54 feet. </span>
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4 years ago
Gcf of 63 and 27 i will give toy 12pts
NeTakaya
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Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
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List three values that would make this inequality true 48x &lt; 6n
anyanavicka [17]
X=1 & Y=12
X=2 & Y=20
X=3 & Y=30
5 0
4 years ago
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