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mel-nik [20]
3 years ago
11

Find the slope of a line perpendicular to each given line

Mathematics
1 answer:
andre [41]3 years ago
8 0

k:\ y=m_1x+b_1\\l:\ y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}

115)\ -x-y=3\ \ \ |+x\\-y=x+3\ \ \ |\cdot(_1)\\y=-x-3\to m_1=-1\to\boxed{m_2=-\dfrac{1}{-1}=1}\\\\116)\ 0=-4x-y+5\ \ \ |+y\\y=-4x+5\to m_1=-4\to\boxed{m_2=-\dfrac{1}{-4}=\dfrac{1}{4}}\\\\117)\ 6-2y=x\ \ \ \ |-6\\-2y=x-6\ \ \ \ |:(-2)\\y=-\dfrac{1}{2}x+3\to m_1=-\dfrac{1}{2}\to\boxed{m_2=-\dfrac{1}{-\frac{1}{2}}=2}\\\\118)\ 5y=25+4x\ \ \ \ |:5\\y=5+\dfrac{4}{5}x\to m_1=\dfrac{4}{5}\to\boxed{m_2=-\dfrac{1}{\frac{4}{5}}=-\dfrac{5}{4}}

119)\ -15x-9y=9\ \ \ \ |+15x\\-9y=15x+9\ \ \ \ |:(-9)\\y=-\dfrac{15}{9}x-1\\y=-\dfrac{5}{3}x-1\to m_1=-\dfrac{5}{3}\to\boxed{m_2=-\dfrac{1}{-\frac{5}{3}}=\dfrac{3}{5}}

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Allisa [31]

Answer: The measure of each exterior angle is 6.4°.

Step-by-step explanation:

Since we have given that

Number of sides = 56

We have to find the measure of each exterior angles:

As we know the formula :

\text{ measure of each exterior angle}=\frac{360^\cir}{\text{Number of sides}}\\\\\text{ measure of each exterior angle}=\frac{360}{56}\\\\\text{ measure of each exterior angle}=6.4^\circ

Hence, the measure of each exterior angle is 6.4°.

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3 years ago
Write the point-slope form of the line passing through (2, -12) and perpendicular to y = 3x.
scoundrel [369]

Answer:

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Step-by-step explanation:

y = 3x

The slope is 3

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Point slope form is

y-y1 = m(x-x1)  where m is the slope and (x1,y1) is the point on the line

y --12 = -1/3(x-2)

y+12 = -1/3(x-2)

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3 years ago
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f/g(x)=(25-x^2)/(x+5)

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