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olganol [36]
3 years ago
6

The Sixth-Graders at Meadowbrook Middle School Are Going On A Field trip. The 325 students and adults will ride in school buses.

Each bus holds 48 people. How many school buses are needed?
Mathematics
2 answers:
aleksklad [387]3 years ago
6 0

We divide 325 by 48.

The answer comes out to 6.77

But since the number of buses must be a whole number, we will need 7 buses to carry the 325 students and teachers on a field trip.

enyata [817]3 years ago
3 0
Remember that you can do anything to an equation as long as you do it to both sides so

we find how many buses needed
 so basically we need at least 325 people spaces
1 bus=48 people spaces
 therefor
 how many buses= 48 times number of busses > 325
 (> means 'is greater than or equal to')
so 48 times number of busses > 325
divide both sides by 48
number of busses > 325/48
 325/48=6 and 37/48
 number of busses > 6 and 37/48
 the number of busses has to be greater that 6 and 37/48
 number of busses also has to be a whole number
 (imagine renting a fractional bus, "Ok, so I need 6 and 37/48 busses. No, I don't want 7 busses, that'll cost extra. Yes, I know what I'm doing. What?! You can't? Why?! You people are so incompetent. Of course I don't want to rent 7 busses. Were just going in circles. Have a nice day! *hangs up*")
so therefor we round 6 and 37/48 up to 7 busses
 the answe ris 7 busses
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i will rate you brainliest// What is the interquartile range (IQR) of {5.8, 8.5, 9.9, -0.8, -1.3, 2.3, 7.4, -1.9}?
Ipatiy [6.2K]

Answer

arrange the element in increasing order

-1.9, -1.3, -0.8, 2.3, 5.8, 7.4, 8.5, 9.9

interquatile = Q3 - Q1

=  \frac{7.4 + 8.5}{2} -  \frac{ - 1.3 - 0.8}{2}

= 7.95  + 1.05

= 9

3 0
3 years ago
Create a set of five positive numbers (repeats allowed) that have a median of 10 and a mean of 14. What thought process did you
Rainbow [258]
We have five value in the data-set

The third value will be 10 since we want the median to be 10

We want the mean to be 14

To find the mean of a data set, we divide the sum of the values by the number of values

Mean = Sum of values ÷ Number of values
14 = Sum of values ÷ 5
Sum of values = 14 × 5
Sum of values = 70

So we need 5 values that add up to 70, one of the value is 10, which is the median. We would want two values that are smaller than 10 and two values more than 10.

These four value must add up to 70 - 10 = 60

From here we can do trial and error:

Choose any two values less than 10, say 9 and 8
We now have in total 8 + 9 + 10 = 27

We have 70 - 27 = 43 left to find
Choose any two values that are bigger than 10 that add up to 43, for example, 20 and 23

Now we have our 5 values; 

8        9         10        20         23

Do the checking bit:

We can see from the set, the median is 10
Mean = [8+9+10+20+23] ÷ 5 = 70 ÷ 5 = 14

We can have values other than 8, 9, 20 and 23 as long as two values smaller than 10 and two values more than 10. All five values must add up to 70.


3 0
4 years ago
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Damm [24]
Copy & paste on googl
5 0
3 years ago
Solve the linear system if 3x+4y-z=-6 5x+8y+2z=2. -x+y+z=0
Anni [7]
We are given with three equations and three unknowns and we need to solve this problem. The solution is shown below:
Three equations are below:
3x + 4y - z = -6
5x + 8y + 2z = 2
-x + y + z = 0

use the first (multiply by +2) and use the second equation:
2 (3x+4y -z = -6)  => 6x + 8y -2z = -12
                               + ( 5x + 8y +2z = 2)
                                  ------------------------
                                     11x + 16y = -10  -> this the fourth equation

use the first and third equation:
 3x + 4y -z = -6
+ (-x + y + z =0)
-------------------------
        2x + 5y = -6 -> this is the fifth equaiton

use fourth (multiply by 2) and use fifth (multiply by -11) equations such as:
2 (11x + 16y = -10)   => 22x + 32y = -20  -> this is the sixth equation
-11 (2x + 5y = -6)    => -22x -55y = 46   -> this is the seventh equation

add 6th and 7th equation such as:
   22x + 32y = -20
+(-22x - 55y = 66)
---------------------------
             - 23y = 46
               <span>   y = -2

solving for x, we have:
</span>2x + 5y = -6 
2x = -6 - 5y
2x = -6 - (5*(-2))
2x = -6 +10
2x = 4
x=2

solving for y value, we have:
-x + y + z =0
z = x -y 
z = 2- (-2)
z =4

The answers are the following:
x = 2
y = -2
z = 4
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4 years ago
Help plz #8 solve the inequality<img src="https://tex.z-dn.net/?f=10%20%2B%20c%20%5Cgeq%2011" id="TexFormula1" title="10 + c \ge
Orlov [11]
The answer is c ≥ 1

Subtract 10 on both sides.

11-10= 1

and that’s how u get ur answer, hope this helped :)
8 0
2 years ago
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