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larisa86 [58]
4 years ago
10

A group of 400 town residents is asked to attend a town hall meeting. Of the 400 residents asked to attend 36 were able to atten

d. What percentage of the town residents were able to attend?
A. 1.1%
B. 90%
C. 11%
D. 9%
Mathematics
1 answer:
zzz [600]4 years ago
5 0
We have to find the percentage ratio of two numbers. It is \frac{36}{400}*100 = 9%. And the correct answer is D). 

Alternatively, by setting up a ratio, we can write that If
                    400_____100%
                      36_____x
And x=9% 
                   
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In the diagram below, BD is parallel to XY. What is the value of y?
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Step-by-step explanation:

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Monica [59]

Expand f(z) into partial fractions:

\dfrac1{z(z-2)} = \dfrac12 \left(\dfrac1{z-2} - \dfrac1z\right)

Recall that for |z| < 1, we have the power series

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Then for |z| > 2, or |1/(z/2)| = |2/z| < 1, we have

\displaystyle \frac1{z-2} = \frac1z \frac1{1 - \frac2z} = \frac1z \sum_{n=0}^\infty \left(\frac 2z\right)^n = \sum_{n=0}^\infty \frac{2^n}{z^{n+1}}

So the series expansion of f(z) for |z| > 2 is

\displaystyle f(z) = \frac12 \left(\sum_{n=0}^\infty \frac{2^n}{z^{n+1}} - \frac1z\right)

\displaystyle f(z) = \frac12 \sum_{n=1}^\infty \frac{2^n}{z^{n+1}}

\displaystyle f(z) = \sum_{n=1}^\infty \frac{2^{n-1}}{z^{n+1}}

\displaystyle \boxed{f(z) = \frac14 \sum_{n=2}^\infty \frac{2^n}{z^n} = \frac1{z^2} + \frac2{z^3} + \frac4{z^4} + \cdots}

6 0
2 years ago
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NeX [460]

Answer:

56% and B

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To calculate her percentage score, create the fraction of her score out of the total and multiply by 100%

percent score = \frac{112}{200} × 100% = 56%

Her percent score is in the interval 50% - 64%

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3 years ago
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Answer:

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