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Travka [436]
4 years ago
9

El hace sus compras por internet el encuentro

Spanish
2 answers:
mezya [45]4 years ago
8 0

Answer

the internet makes shopping for the meeting

Gnom [1K]4 years ago
7 0
He shops online he found..
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Simplify x^3-125/2x-10
MAVERICK [17]
We \ first, \ simplify \  \frac{125}{2} \\ \\   \left[\begin{array}{ccc}((x^3)-( \frac{125}{2}*x))-10 \end{array}\right] \\ \\ \boxed{\boxed{x^3= \frac{x^3}{1} = \frac{x^3*2}{2} }} \\ \\ \\ \boxed{ \frac{x^3*2-(125x)}{2} = \frac{2x^3-125x}{2} } \\ \\ \\ \frac{(2^3-125x}{2} -10 \\ \\  pulling \ out \ like \ factors : \\ \\  2x^3 - 125x  =   x * (2x^2 - 125) \\ \\ Factoring: \  2x^2 - 125

<span>Here's how!</span>

Proof :  \ (A+B) * (A-B) =\\&#10;         A2 - AB + BA - B2 =\\&#10;         A2 - AB + AB - B2 = \\&#10;         A2 - B2\\

<span>Therefore</span> . . . 

\boxed{ \frac{x*(2x^2-125)-(10*2)}{2} = \frac{2x^3-125x-20}{2} }

<span>The factors would then be the following:</span>

→ ( Leading \  Coefficient :  1,2)
→ (Trailing Constant) :  1 ,2 ,4 ,5 ,10 ,20

By then, understanding on how we have got in our terms, such as the like terms, and also how we have understanded the coefficient's, we would then have our answer clear below.

\leadsto \ Your \ answer: \boxed{\bf{ \frac{2x^3-125x-20}{2} }} <span>✔</span>
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