Question

Among a particular population of 100 plants, red flowers are dominant and yellow flowers are recessive. F is the dominant allele and f is the recessive allele. 40 plants are homozygous dominant 44 plants are heterozygous 16 plants are homozygous recessive Use the Hardy-Weinberg equation to calculate the equilibrium frequencies of each genotype.

Answer 1

Answer:

The genotype of the homozygous dominant will be FF, and the total number of F alleles will be 40 × 2 = 80.

The genotype of the heterozygous plant types will be Ff. There will be 44 F alleles and 44 f alleles.

The genotype of the homozygous recessive will be ff, and the total number of f alleles will be 16 × 2 = 32.

Now the total number of alleles is 200 [(40 × 2) + 44 + 44 + (16 × 2)].

The frequency T of F allele will be .

The frequency t of f allele will be .

Now the frequency of the genotypes is represented by the equation p2+2pq+q2 = 1.

So, (0.62 × 0.62) + 2(0.62 × 0.38) + (0.38 × 0.38) = 1.Or (0.3844) + (0.4712) + (0.1444) = 1.

The genotype of the homozygous dominant will be FF, and the total number of F alleles will be 40 × 2 = 80.

The genotype of the heterozygous plant types will be Ff. There will be 44 F alleles and 44 f alleles.

The genotype of the homozygous recessive will be ff, and the total number of f alleles will be 16 × 2 = 32.

Now the total number of alleles is 200 [(40 × 2) + 44 + 44 + (16 × 2)].

The frequency T of F allele will be .

The frequency t of f allele will be .

Now the frequency of the genotypes is represented by the equation p2+2pq+q2 = 1.

So, (0.62 × 0.62) + 2(0.62 × 0.38) + (0.38 × 0.38) = 1.Or (0.3844) + (0.4712) + (0.1444) = 1.

So, homozygous dominant frequency is 0.3844;heterozygous dominant frequency is 0.4712; and homozygous recessive frequency is 0.1444.

Explanation:

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