Given that h(x) = |12x - 4| + 6, what is the value of x when h(x) = 4?

Rectangle ABCD with coordinates A(1, 1), B(4, 1), C(4, 2), and D(1, 2) dilates with respect to the origin to give rectangle A'B'

Virty [35]

Scale factor is a ratio. The correct option is C.

<h3>How are scale drawings formed?</h3>

For a particular scale drawing, it is already specified that all the measurements' some constant scaled version will be taken. For example, let the scale be K feet to s inches.

Then it means

$\rm 1\: ft : \dfrac{s}{k}\: in.$

All feet measurements will then be multiplied by s/k to get the drawing's corresponding lengths.

The length of AB can be written as,

AB = √[(1-4)²+ (1-1)²]

AB = 3

Since the length A'B' is 6 units, therefore, the scale factor will be,

Scale factor = (Length after transformation)/(Length before transformation)

Scale factor = 6 /3 = 2

Hence, the correct option is C.

Learn more about Scale factors:

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8 0

2 years ago

Can you please explain how you got the answer? Also plz tell me what the closed and open circle mean again..

ale4655 [162]

Answer: A

Step-by-step explanation:

Open circle means that x does not equal that number. For example, the open circle on C is on 8, so that shows x is not equal to 8.

Closed circle means that x does equal that number. For example on A, there is a closed circle on 8, so x could equal 8.

First, we need to solve the equation.

Subtract 200 frim 1200 -> 125x ≥ 1000.
Divide 125 from 1000 to isolate the x -> x ≥ 8

So, that means x is bigger than or equal to 8.

8 0

3 years ago

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(HELP ASAP)In the figure, if OQ is the angle bisector of ∠POR, find m∠POQ.

umka21 [38]

Answer:

61°

Step-by-step explanation:

$9x+7=13x-17$ , QO Bisector

$x=6\\$ , Algebra

$m$ , Algebra/Sub

6 0

3 years ago

(NEED HELP! WILL RATE 5 STARS!)

vitfil [10]

Answer:I think it's 1/61

Step-by-step explanation:If I am correct plz don't forget to thank me...

3 0

3 years ago

M is the midpoint of AN, A has coordinates

maksim [4K]

Step-by-step explanation:

According to Question , M is the midpoint of AN, A has coordinates (-7,4), and M has coordinates (-4, -1).

Figure :-

$\setlength{\unitlength}{1 cm}\begin{picture}(20,12) \put(4,0.2){\line(0,-1){0.4}}\put(1,0){\line(1,0){6}} \put(3.8,-0.6){$\bf M(-4,-1) $} \put(1,-0.6){$\bf A (-7,4)$} \put(6.8,-0.6){$\bf N(x,y)$} \end{picture}$

Let the coordinates of N be ( x , y )

Now , according to Midpoint Formula , the midpoint of points say A(x , y) and B (x' , y') is given by ,

$\boxed{\blue{ \bf Midpoint =\bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) }}$

On using this formula ,

$=> Midpoint = \bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) \\ \\ => (-4, 1) = \bigg( \dfrac{x -7 }{2} , \dfrac{y + 4 }{2}\bigg) \\ \\ => -4 = \dfrac{x-7}{2} \\\\ => x - 7 = -8 \\\\ => x = 7 -8 \\\\ \boxed{\red{\sf=> x = -1 }} \\\\ => \dfrac{y+4}{2}=-1 \\\\=> y +4 = -2 \\ \\ y = -4-2 \\\\\boxed{\red{\sf=> y = -6 }}$

8 0

3 years ago

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