Answer:
54 m
Step-by-step explanation:
Alrighty, what have we here: an area of 162 m² and a width of 9m.
So: A=162m², W=9m, let's draw this: (see the screenshot attached)
Using the formula for area (Area = width x length) we see that:
Thus: (equating to L by dividing both sides by 9m)
⇒ 
Now we have all of our dimensions, we can use the formula for the perimeter to calculate it:
And there we have our answer.
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
1 whole should be the answer
Answer:
- A. 3x° + (8x - 20)° = 90°
Step-by-step explanation:
The two given angles are complementary and sum to 90°
Therefore correct choice is A.
Answer:
<2 ≅<4 with reason of vertical angle theorem.
Step-by-step explanation:
The vertical angle theorem states that two opposite (non-adjacent) angles formed by 2 intersecting lines have equal measure. In this problem, we are given that the angles are vertical angles. So the statement is that <2 ≅<4 with reason of vertical angle theorem.
