Question

Please help and explain how to do this. thank you in advance!

Answer 1

We want to solve
$3e^{2x}+5=27$

Subtract 5 from each side.
$3e^{2x}=22$
Divide each side by 3.
$e^{2x}=7.3333$
Take natural logs of each side.
$2x=ln(7.3333)=1.9924$
Divide each side by 2.
x = 0.9962

Answer:  x = 0.996  (nearest thousanth)