3 years ago

Please help and explain how to do this. thank you in advance!

1 answer:

6 0

We want to solve
$3e^{2x}+5=27$

Subtract 5 from each side.
$3e^{2x}=22$
Divide each side by 3.
$e^{2x}=7.3333$
Take natural logs of each side.
$2x=ln(7.3333)=1.9924$
Divide each side by 2.
x = 0.9962

Answer: x = 0.996 (nearest thousanth)

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