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bekas [8.4K]
3 years ago
14

1/3(x+3) - 2/x+3, where x is not equal to negative 3

Mathematics
1 answer:
myrzilka [38]3 years ago
5 0
If x\neq 3, then

\frac{1}{3(x+3)} - \frac{2}{x+3} = \frac{1\cdot 1-2\cdot 3}{3(x+3)} = \frac{-5}{3(x+3)} =- \frac{5}{3(x+3)}.

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luda_lava [24]
Where's the graph?  Insufficient info here to enable us to answer this question.
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8 0
3 years ago
Can anyone help me with this please ?
zlopas [31]
   
\displaystyle \bf\\
 \frac{x}{20} =  \frac{14}{25}  \\  \\  \\ 
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7 0
3 years ago
-3/8a + 3.2b + (-6b) -1/4a<br><br> I am not sure about this question please help!
expeople1 [14]

Answer:

-5/8a - 2.8b

Step-by-step explanation:

-3/8a + 3.2b + (-6b) - 1/4a

=> -3/8a + 3.2b + (-6b) - 2/8a

=> -5/8a + 3.2b - 6b

=> -5/8a - 2.8b

Therefore, -5/8a - 2.8b is the solution to your problem.

Hoped this helped.

5 0
3 years ago
A school wishes to accept 2000 students for their freshman class, and they expect 20,000 applications. In order to make their ad
vovangra [49]

Answer:

456

Step-by-step explanation:

Let X be the SATscore scored by the students

Given that X is normal (1000,200)

By converting into standard normal variate we can say that

z=\frac{x-1000}{200} is N(0,1)

To find the top 10% we consider the 90th percentile for z score

Z 90th percentile = 1.28

X= 200+1.28(200)\\= 200+256\\=456

i.e. only students who scored 456 or above only should be considered.

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4 years ago
−1 3/5 ​÷ 5/-6 <br><br> khan academy
Fittoniya [83]

Answer:

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5 0
3 years ago
Read 2 more answers
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