The perimeter of a square is 28 cm . What is the area

PLEASE HELP IM DESPERATE ALL I NEED IS FOR SOMEONE TO ANSWER NUMBERS 7, 8, AND 9

andrezito [222]

Answer:

The answer to 9 is below

Step-by-step explanation:

2(L + W) = P

2(W + 5a - b) = 16a + 2b

2(W + 5a - b) = 2(8a + b)

W + 5a - b = 8a + b

W = 3a + 2b

8 0

3 years ago

Van is studying the effects of an indoor pool

Artyom0805 [142]

Answer:

The answer is C

Step-by-step explanation:

hope this helps

7 0

3 years ago

40000+10000n= how do i find the answer

klasskru [66]

Answer:

50000. easy

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Jim would like to create a pencil holder with no top. He would like it to be 5 inches tall and 3 inches wide. He cannot decide i

maw [93]

Answer:

$\$11.13$

Step-by-step explanation:

step 1

Find the surface area of the cylinder

The surface area of the cylinder is equal to

$SA=\pi r^{2} +2\pi rh$

we have

$r=3/2=1.5\ in$ ----> the radius is half the diameter

$h=5\ in$

assume

$\pi =3.14$

substitute

$SA=(3.14)(1.5)^{2} +2(3.14)(1.5)(5)=54.165\ in^{2}$

Find the cost

$54.165*(0.75)=\$40.62$

step 2

Find the surface area of the square prism

The surface area of the prism is equal to

$SA=b^{2} +4bh$

we have

$b=3\ in\\ h=5\ in$

substitute

$SA=(3)^{2} +4(3)(5)=69\ in^{2}$

Find the cost

$69*(0.75)=\$51.75$

step 3

Find the difference of costs

$\$51.75-\$40.62=\$11.13$

5 0

4 years ago

In a survey, 32% of the respondents stated that they talk to their pets on the telephone. A veterinarian believed this result

adoni [48]

Answer:

$z=\frac{0.29 -0.32}{\sqrt{\frac{0.32(1-0.32)}{210}}}=-0.932$

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of pet owners contacted by telephone is NOT significantly lower than 0.32

Step-by-step explanation:

Data given and notation

n=210 represent the random sample taken

X=61 represent the number of pet owners contacted by telephone

$\hat p=\frac{61}{210}=0.29$ estimated proportion of pet owners contacted by telephone

$p_o=0.32$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportions is lower than 0.32.:

Null hypothesis: $p \geq 0.32$

Alternative hypothesis: $p < 0.32$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.29 -0.32}{\sqrt{\frac{0.32(1-0.32)}{210}}}=-0.932$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of pet owners contacted by telephone is NOT significantly lower than 0.32

3 0

3 years ago