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sesenic [268]
4 years ago
6

Find the geometric mean between each pair of numbers.

Mathematics
1 answer:
sasho [114]4 years ago
6 0
\text{The geometric mean:}\ \sqrt[n]{a_1\cdot a_2\cdot...\cdot a_n}

\sqrt{28\cdot7}=\sqrt{4\cdot7\cdot7}=\sqrt{4\cdot49}=\sqrt4\cdot\sqrt{49}=2\cdot7=14

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A family purchased tickets for a concert. They paid a total of $90 for 7 adult tickets and 12 child tickets. The price of a chil
Anit [1.1K]

Answer: 7 + 2/3(12) = 15

90/15 = $6 for adult tickets


7 0
3 years ago
STRUCTURE A quality control inspector at a bolt factory examines random bolts that come off the assembly line. All bolts being m
ELEN [110]

From an absolute value inequality, we have that:

  • The minimum diameter is 6.46 mm.
  • The maximum diameter is 6.54 mm.

  • The absolute value measures the <u>distance of a point or a function to the origin</u>.
  • One example of inequality is:

|f(x)| \leq a

Which has solution:

-a \leq f(x) \leq a

In this problem:

  • Bolts with a diameter of 6.5 mm, with a tolerance of 0.04 mm, thus the <u>absolute value of the difference of the diameter D and 6.5 has to be of at most 0.04</u>, that is:

|D - 6.5| \leq 0.04

Applying the solution:

-0.04 \leq D - 6.5 \leq 0.04

-0.04 \leq D - 6.5

D - 6.5 \geq -0.04

D \geq 6.46

\leq D - 6.5 \leq 0.04

D \leq 6.54

  • The minimum diameter is 6.46 mm.
  • The maximum diameter is 6.54 mm.

A similar problem is given at brainly.com/question/24835634

5 0
3 years ago
Can I know if part c is correct? ​
AlekseyPX
Yeah, part C seems right to me. Have a good day or night !
5 0
4 years ago
The Pringles manufacturer wants the margin of error for the mean weight of cans to be within 0.5 ounces. For a confidence interv
polet [3.4K]

Answer: Sample size required is 35

Step-by-step explanation:

The attachment below shows the calculations.

6 0
3 years ago
100 points , please help. I am not sure if I did this correct if anyone can double-check me thanks!
Nookie1986 [14]

Step-by-step explanation:

\lim_{n \to \infty} \sum\limits_{k=1}^{n}f(x_{k}) \Delta x = \int\limits^a_b {f(x)} \, dx \\where\ \Delta x = \frac{b-a}{n} \ and\ x_{k}=a+\Delta x \times k

In this case we have:

Δx = 3/n

b − a = 3

a = 1

b = 4

So the integral is:

∫₁⁴ √x dx

To evaluate the integral, we write the radical as an exponent.

∫₁⁴ x^½ dx

= ⅔ x^³/₂ + C |₁⁴

= (⅔ 4^³/₂ + C) − (⅔ 1^³/₂ + C)

= ⅔ (8) + C − ⅔ − C

= 14/3

If ∫₁⁴ f(x) dx = e⁴ − e, then:

∫₁⁴ (2f(x) − 1) dx

= 2 ∫₁⁴ f(x) dx − ∫₁⁴ dx

= 2 (e⁴ − e) − (x + C) |₁⁴

= 2e⁴ − 2e − 3

∫ sec²(x/k) dx

k ∫ 1/k sec²(x/k) dx

k tan(x/k) + C

Evaluating between x=0 and x=π/2:

k tan(π/(2k)) + C − (k tan(0) + C)

k tan(π/(2k))

Setting this equal to k:

k tan(π/(2k)) = k

tan(π/(2k)) = 1

π/(2k) = π/4

1/(2k) = 1/4

2k = 4

k = 2

8 0
4 years ago
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