Question

F(x)=x^2-3x+7 and g(x)=x+3 solve f(x)=g(x)

Answer 1

For this case we have the following functions:

$f (x) = x ^ 2-3x + 7\\g (x) = x + 3$

Equalizing we have:

$x ^ 2-3x + 7 = x + 3\\x ^ 2-3x-x + 7-3 = 0\\x ^ 2-4x + 4 = 0$

To solve we factorize, that is, we look for two numbers that when multiplied give a result of 4 and when added together give a result of -4. These numbers are -2 and -2.

$-2-2 = -4\\(-2) * (- 2) = 4$

Thus, we have:

$(x-2) (x-2) = 0\\(x-2) ^ 2 = 0$

So, the solution is$x = 2$

Answer:

$x=2$