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notka56 [123]
3 years ago
15

The proteins and dna of organisms that share a recent common ancestor are more ____________________ than the proteins and dna of

organisms that do not share a recent common ancestor.
Biology
1 answer:
likoan [24]3 years ago
6 0
Similar is the answer

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Nate has a track meet after school. He wants to select an item for lunch
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Mendel crossed homozygous tall and short plants. The law of segregation dictates that each sperm of the tall plant randomly pass
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Answer:

D.) If the homozygous tall plant (TT) crosses with a homozygous short plant (tt), then all the F1 plants become heterozygous tall plants (Tt).

Explanation:

Homozygous indicates that the alleles in the genotype are the same. Therefore, the genotype for homozygous tall plants is (TT) and the genotype for homozygous short plants is (tt).

After performing a cross, we know that all of the children will have the heterozygous genotype (Tt).

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14). During the early 1700’s, a small group of pacifist Protestants fled Germany to avoid religious persecution. This group, the
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A) In the Dunker population, the frequency of IB allele is 0.3 and the frequency of i allele is 0.4. In the general population, the frequency of IB allele is 0.1 and t<span>he frequency of i allele is 0.5.
</span>
If:
I^{A} - <span>the frequency of IA allele
</span>I^{B} - <span>the frequency of IB allele
</span>i - t<span>he frequency of i allele

Then:
</span>I^{A} I^{A} + <span>I^{A} i - the frequency of individuals with A blood type
</span>I^{B} I^{B} + <span>I^{B} i - the frequency of individuals with B blood type
</span>ii <span>- the frequency of individuals with O blood type
</span>
Let's first take a look on the Dunker population:
I^{A} = 0.3
ii=0.16&#10;

<span>Since there is only one possible genotype for O individuals - ii - the frequency of the allele i is square root of the frequency of O individuals:
</span>i= \sqrt{ii}
⇒ i =  \sqrt{0.16}
⇒ i=0.4

Now, we have the frequencies of two alleles (I^{A} and i). To calculate the frequency of I^{B}<span> allele, we will use the formula:
</span>I^{A} + I^{B} + i = 1
⇒ I^{B} = 1- I^{A} - i
⇒ I^{B} = 1-0.3-0.4
⇒ I^{B} = 0.3

Now, in the general population:
I^{A} = 0.4
ii=0.25

<span>Similarly to the work for the Dunker population:
</span>i= \sqrt{ii}
⇒ i = \sqrt{0.25}
⇒ i=0.5

I^{A} + I^{B} + i = 1
⇒ I^{B} = 1- I^{A} - i
⇒ I^{B} = 1-0.4-0.5
<span>⇒ I^{B} = 0.1
</span>


b) A founder effect is a result of geographical separation of a few individuals from the original population. Those founding individuals will form a new population. The Dunker population was not only geographically separated, but also genetically. The group interbreeding was present resulting in increasing those allele frequencies that were the most common in the founding population. In this case, the most individuals from the founding population had B blood type.
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A student does an experiment for a science fair to study whether temperature affects the timing of a cricket’s chirps. The stu
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The frequency of chirps increases as the temperature increases. The correct option is B. <em>The chirps occur closer together as the temperature increases.  </em>

-------------------------------

<h2><u>Available data:</u></h2>

<h3>Data recorded by the student </h3>

<em><u>Day      Temperature   Average time between chirps (sec)</u></em>

1            21                             2. 5

2           22                            2. 6

3           23                            2. 2

4           24                            2. 3

5           25                            2. 0

6           26                             1. 8

7           27                              1. 9

8           28                             1. 8

9          29                             1. 4

10          30                             1. 2

11           31                              1. 5

<u>12          32                             1. 1</u>

In this experiment the student recorded the time in seconds <u>between </u><u>chirps</u>.

We can see that <em>as the </em><em>temperature increases</em><em>, in general, the</em><em> time</em><em> between</em><em> chirps decreases</em>.

  • At 21ºC the time between chirps is 2.5 seconds
  • At 26ºC the time between chirps is 1.8 seconds
  • At 32ºC the time between chirps is 1.1 seconds

According to this information, if the average time between chirps decreases with the temperature increase, we can assume that<em> the </em><em>frequency</em><em> of chirps </em><em>increases</em><em> as the temperature gets higher. </em>

<h3>Options,</h3>

<em>A) The higher the temperature, the fewer chirps there will be in 10 seconds</em>.

Wrong. The number of chirps in 10 seconds will depend, not only on the frequency but also on how long the chirps last. Since the student did not record the time of chirps, we can not make this conclusion.  

<em>B) The chirps occur closer together as the temperature increases</em>.

True. The chirps increase in frequency as the temperature increases, so they occur closer together.

<em>C) The chirps become farther apart as the temperature increases</em>.

Wrong. We can see how the time between chirps decreases as temperature increases, meaning that they are closer not farther.

D) There is no relationship between temperature and the time between chirps.

Wrong. If we make a graph we will see the tendency and the relationship between chirps and temperature.

Graphs usually explain the relationship between variables. In this example, the relationship would be inverse.

-------------------------------------

You can learn more about

at brainly.com/question/15210301

5 0
3 years ago
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