3 years ago

Log(x^2 +5x+16) = 1 solve for x

1 answer:

7 0

$D:x^2+5x+16\ \textgreater \ 0\\
D:x\in\mathbb{R}\\\
\log(x^2+5x+16)=1\\
10^1=x^2+5x+16\\
x^2+5x+6=0\\
x^2+2x+3x+6=0\\
x(x+2)+3(x+2)=0\\
(x+3)(x+2)=0\\
x=-3 \vee x=-2$

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