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Pani-rosa [81]
3 years ago
11

Log(x^2 +5x+16) = 1 solve for x

Mathematics
1 answer:
Rasek [7]3 years ago
7 0
D:x^2+5x+16\ \textgreater \ 0\\
D:x\in\mathbb{R}\\\
\log(x^2+5x+16)=1\\
10^1=x^2+5x+16\\
x^2+5x+6=0\\
x^2+2x+3x+6=0\\
x(x+2)+3(x+2)=0\\
(x+3)(x+2)=0\\
x=-3 \vee x=-2
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Step-by-step explanation:

1. You can divide 1/3 by 5 by changing the division symbol to its reciprocal, multiplication, and also divide by the reciprocal of the number after the symbol, 5. The reciprocal of 5 is 1/5.

2. Now you can do 1/3 multiplied by 1/5. Multiply the numerators by the denominators. The numerators are 1 and 1, so you multiply 1 by 1 which equals 1. Now you multiply the denominators, 3 and 5, which is equal to 15. If the numerator is now 1, and the denominator is 15, the new fraction is 1/15, getting you to your answer

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3 years ago
Ayush and sumit take two different routes to school. Ayush's route is 1km 2hm long while sumit route is 2hm 30dam long while rou
emmasim [6.3K]

Answer:

Ayush's route is 0.7 km or 700m longer than Sumit route.

Step-by-step explanation:

Ayush's route is 1km 2hm long while sumit route is 2hm 30dam.

We know that,

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Using these conversions we get

Ayush's route = 1km 2hm = (1×10) hm + 2 hm = 12 hm

Sumit route = 2hm 30dam = 2 hm + (30×0.1) hm = 2 hm + 3 hm = 5 hm

Ayush's route is longer.

Difference = 12 hm - 5 hm = 7 hm = 0.7 km            [1 km = 10 hm]

Hence, Ayush's route is 0.7 km or 700 m longer than Sumit route.

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