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Vitek1552 [10]
3 years ago
9

How to do fractions

Mathematics
2 answers:
Elodia [21]3 years ago
8 0
Look it up or study they are not that hard
stellarik [79]3 years ago
4 0
Use the bridge. the one on the bottom stays on the outside of the bridge and the on the top stays under the bridge.
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Which route must use all of the vertices of a vertex-edge graph? (Check all that apply.)
zlopas [31]

An Euler path, in a graph or multi graph, is a walk through the graph which uses every edge exactly once. An Euler circuit is an Euler path which starts and stops at the same vertex. Our goal is to find a quick way to check whether a graph (or multi graph) has an Euler path or circuit.


                                   


                                                 hope it helps

4 0
3 years ago
Read 2 more answers
Write an explanation for both Part A and Part B using 3-4 complete sentences. Part A: Explain how you can determine if a system
vampirchik [111]

Answer:

Step-by-step explanation:

Part A : when comparing graphs : A system of equations will have no solutions (on a graph) when your lines never cross each other. They never cross each other because your lines are parallel.

Part B : by comparing each algebraic equation : A system of equations will have no solution if your lines are parallel. Parallel lines will have the same slope but different y intercepts. Example :

2x - y = 2

4x - 2y = 8

put both equations in slope intercept form

y = 2x - 2

y = 2x - 4

they both have the same slope of 2.....and the y intercepts are different....meaning they are parallel lines and have no solutions

7 0
3 years ago
Which expressions are equivalent to \dfrac{4^{-3}}{4^{-1}} 4 −1 4 −3 ​ start fraction, 4, start superscript, minus, 3, end super
Slav-nsk [51]

Answer:

\dfrac{4^{-3}}{4^{-1}} = \dfrac{4^{1}}{4^{3}}

\dfrac{4^{-3}}{4^{-1}} = \dfrac{1}{4^{2}}

Step-by-step explanation:

Given

\dfrac{4^{-3}}{4^{-1}}

Required

Choose equivalent expressions

Choosing the first answer:

\dfrac{4^{-3}}{4^{-1}}

Split expressions

4^{-3} * \frac{1}{4^{-1}}

Apply laws of indices: (a^{-b} = \frac{1}{a^b})

\frac{1}{4^3} * \frac{1}{4^{-1}}

Apply laws of indices: (a^{-b} = \frac{1}{a^b})

\frac{1}{4^3} * \frac{1}{1/4}

\frac{1}{4^3} * \frac{4^1}{1}

\frac{4^1}{4^3}

Hence:

\dfrac{4^{-3}}{4^{-1}} = \dfrac{4^{1}}{4^{3}}

Choosing the second:

\dfrac{4^{-3}}{4^{-1}}

Apply law of indices: (\frac{a^m}{a^n} = a^{m-n})

So,

\dfrac{4^{-3}}{4^{-1}} = 4^{-3-(-1)}

\dfrac{4^{-3}}{4^{-1}} = 4^{-3+1)}

\dfrac{4^{-3}}{4^{-1}} = 4^{-2}

Apply law of indices: (a^{-b} = \frac{1}{a^b})

So:

\dfrac{4^{-3}}{4^{-1}} = \dfrac{1}{4^{2}}

4 0
3 years ago
I need to know the answer and how you got there. I suck at math and my kids answers aren’t part of the answer key.
enot [183]

Answer:

Why is a parent on Brainly??? Kinda weird><>

Step-by-step explanation:

5 0
3 years ago
Sandra needs 4 1/4 cups of flour for one kind of cookie and 3 1/8 cups for another kind. How much would she need for both kinds
Mice21 [21]

For both kinds she needs:

4 1/4 + 3 1/8= 7 3/8

So for both kinds she needs 7 3/8 cups.

3 0
3 years ago
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