Answer:
(14-9i)+(2+3i) = 16-6i
Step-by-step explanation:
We need to find the equivalent of (14-9i)+(2+3i).
We need to add the two expressions.
(14-9i)+(2+3i) = 14+2 -9i+3i
= 16-6i
Here, the real part is 16
The imaginary part is -6
Hence, the required answer is equal to 16-6i.
You put all the numbers on one side of the equation and letters on another.
0.25r + 0.5r - r = 0.5 +0.125
-0.75r = 0.625 divide both sides by -0.75
r = -0.125
Answer:find the solution to the system of equations below.start by adding the equation
{-2x+2y=-8
{2x+y=5
Step-by-step explanation:The given system of equation are:
1---- y= x -4
2----- y=4 x+2
Equation (1) - Equation (2)
→0= x -4 - (4 x+2)
→0= -3 x -6-----[Adding and subtracting like terms]
Adding 3 x on both sides
→3 x= -6
Dividing by 3 on both sides
→x = -2
→Substituting the value of x in equation 1, we get
y= -2 -4
y =-6
→Solution set =(x,y)=(-2, -6)
Don't used the graph to find the solution.
