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arsen [322]
3 years ago
5

Last Tuesday regal cinemas sold a total of 8500 movie tickets. Proceeds totaled $64605. Tickets can be bought in 3ways :matinee

cost 5$, students cost 6$ all day and regular cost 8$. How many of each type of tickets was sold if twice as many students tickets were sold as matinee tickets ?
Mathematics
1 answer:
Vlad [161]3 years ago
6 0

Answer: 485 matinee tickets, 7045 regular tickets and 970 student tickets were sold.

Step-by-step explanation:

Let x represent the number of matinee tickets that were sold.

Let y represent the number of regular tickets that were sold.

Let z represent the number of student tickets that were sold.

Last Tuesday regal cinemas sold a total of 8500 movie tickets. It means that

x + y + z = 8500

Tickets can be bought in 3ways :matinee cost $5, students cost $6 all day and regular cost $8. Proceeds totaled $64605. It means that

5x + 8y + 6z = 64605- - - - - - - - -2

if twice as many students tickets were sold as matinee tickets, it means that

z = 2x

Substituting z = 2x into equation 1 and equation 2, it becomes

x + y + 2x = 8500

3x + y = 8500

y = 8500 - 3x - - - - - - - - - 3

5x + 8y + 6 × 2x = 64605

5x + 8y + 12x = 64605

17x + 8y = 64605- - - - - - - - - 4

Substituting equation 3 into equation 4, it becomes

17x + 8(8500 - 3x) = 64605

17x + 68000 - 24x = 64605

17x - 24x = 64605 - 68000

- 7x = - 3395

x = - 3395/-7

x = 485

z = 2x = 2 × 485

z = 970

Substituting x = 485 and z = 970 into equation 1, it becomes

485 + y + 970 = 8500

1455 + y = 8500

y = 8500 - 1455

y = 7045

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